All categories

3 years ago

Help me with this look at the photo and help me answer all the questions please and thanks

Mathematics

1 answer:

Nataliya [291]3 years ago

5 0

Answer:

1104seconds and5 milliseconds

(8209-6000)/2

=3209/2

=1104.5

The scientists will reach the ocean floor after 1104.5 seconds.

Please mark me as the brainiest and follow me!Hope that helps ;)

You might be interested in

Translate the phrase into a variable expression.

Viktor [21]

"the product of" ⇒ ___ * ___

86 ⇒ 86 . . . . . fills first blank

and

the depth of the river ⇒ d . . . . . fills second blank.

Your expression is

86 * d

4 0

3 years ago

Movie critics claim that 68% of adults and 79% of teenagers would recommend seeing the newest action movie.

tangare [24]

Answer:

no hablo ingles

Step-by-step explanation:

??y voy a 5c

3 0

2 years ago

The volume of a spherical balloon is increasing at the rate of 25cm^3/min, how fast is the radius increasing when the radius is

S_A_V [24]

Answer:

So the radius is increasing at $\frac{1}{64\pi} \frac{\text{cm}}{\text{min}}$ .

This is approximately 0.00497 cm/min that the radius is increasing.

Step-by-step explanation:

$V=\frac{4}{3}\pi r^3$

The volume and radius are both things that are changing with respect to time.

So their derivatives will definitely not be 0.

Let's differentiate:

$V'=\frac{4}{3} \pi \cdot 3r^2r'$

I had to use constant multiple rule and chain rule.

We are given $V'=+25 \frac{\text{cm^3}}{\text{min}}$ and $r=20 \text{cm}$ .

We want to find $r'$ .

Let's plug in first:

$25=\frac{4}{3}\pi \cdot 3(20)^2r'$

$25=\frac{4}{3} \pi \cdot 3(400)r'$

$25=\frac{4}{3} \pi \cdot 1200r'$

Multiply both sides by 3:

$75=4 \pi \cdot 1200r'$

$75=4800 \pi r'$

Divide both sides by $4800 \pi$ :

$\frac{75}{4800 \pi}=r'$

$\frac{1}{64 \pi}=r'$

So the radius is increasing at $\frac{1}{64\pi} \frac{\text{cm}}{\text{min}}$ .

This is approximately 0.00497 cm/min that the radius is increasing.

5 0

3 years ago

Read 2 more answers

Select all that apply

Anastaziya [24]

Answer:

<h2>Third option</h2>

$\log _{10}\left(20x^5\right)-1\\$

Step-by-step explanation:

$5\log _{10}\left(x\right)+\log _{10}\left(20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\\\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)\\\\5\log _{10}\left(x\right)=\log _{10}\left(x^5\right)\\\\=\log _{10}\left(x^5\right)+\log _{10}\left(20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\\\quad \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)\\\\\log _{10}\left(x^5\right)+\log _{10}\left(20\right)=\log _{10}\left(20x^5\right)\\\\$

$=\log _{10}\left(x^5\cdot \:20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1\\\\=\log _{10}\left(20x^5\right)-1$

5 0

3 years ago

Read 2 more answers

F(x, y, z) = yz i + xz j + (xy + 18z) k c is the line segment from (1, 0, −1) to (5, 6, 1) (a) find a function f such that f = ∇

bearhunter [10]

$\nabla f(x,y,z)=\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j+\dfrac{\partial f}{\partial z}\,\mathbf k=\mathbf f(x,y,z)$

$\displaystyle\int\frac{\partial f}{\partial x}\,\mathrm dx=\int yz\,\mathrm dx$
$\implies f(x,y,z)=xyz+g(y,z)$
$\dfrac{\partial f}{\partial y}=xz+\dfrac{\partial g}{\partial z}=xz$
$\implies\dfrac{\partial g}{\partial z}=0$
$\implies g(y,z)=h(z)$

$\dfrac{\partial f}{\partial z}=xy+\dfrac{\mathrm dh}{\mathrm dz}=xy+18z$
$\implies\dfrac{\mathrm dh}{\mathrm dz}=18z$
$\implies h(z)=9z^2+C$

$\implies f(x,y,z)=xyz+9z^2+C$

$\implies\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(5,6,1)-f(1,0,-1)=30$

6 0

3 years ago