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3 years ago

Kate sets a goal to walk 3 miles every day for a year. How many miles more or less than 1000 miles will she walk in the year

Mathematics

1 answer:

Law Incorporation [45]3 years ago

6 0

Answer:

Step-by-step explanation:

365x3=1095

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What is the speed of a baseball that travels 49 meters in 2.4 seconds

kotykmax [81]

Answer:

Speed of baseball = $20.417m/s$

Step-by-step explanation:

Speed of a object is the total distance traveled per unit total time taken to cover that distance.

$SPEED=\frac{DISTANCE}{TIME}$

Given:

Distance= 49 meter Time =2.4 seconds

Speed = $\frac{49}{2.4}$

= $\frac{490}{24}$

Speed of the baseball = $20.417m/s$

The speed of baseball is $20.417m/s$

7 0

3 years ago

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In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study

astra-53 [7]

Answer:

C. z = 2.05

Step-by-step explanation:

We have to calculate the test statistic for a test for the diference between proportions.

The sample 1 (year 1995), of size n1=4276 has a proportion of p1=0.384.

$p_1=X_1/n_1=1642/4276=0.384$

The sample 2 (year 2010), of size n2=3908 has a proportion of p2=0.3621.

$p_2=X_2/n_2=1415/3908=0.3621$

The difference between proportions is (p1-p2)=0.0219.

$p_d=p_1-p_2=0.384-0.3621=0.0219$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{1642+1415}{4276+3908}=\dfrac{3057}{8184}=0.3735$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3735*0.6265}{4276}+\dfrac{0.3735*0.6265}{3908}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00006}=\sqrt{0.00011}=0.0107$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.0219-0}{0.0107}=\dfrac{0.0219}{0.0107}=2.05$

z=2.05

4 0

3 years ago

Need help please anyone ?

Tresset [83]

Answer:

The mean would be 14.4 hours.

Step-by-step explanation:

In order to find the mean, or average, of the numbers, you would add all the numbers together.

17 + 15 +14 + 14 + 12 which equals 72

Then, you take the total which is 72, and divide it by how many numbers you added together which is 5.

72/5 = 14.4

5 0

3 years ago

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The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

8 0

3 years ago

Billy wants to find out which cafeteria food is the favorite in his school for students. He surveys 100 students. 29 students se

Pani-rosa [81]

9/25 it’s simplified

6 0

2 years ago

Read 2 more answers