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Thepotemich [5.8K]
4 years ago
7

Specialized cells regulate the expression of genes because they

Biology
2 answers:
Tamiku [17]4 years ago
4 0
The answer is D,

<span>A. do not want the genes to become worn out.
B. cannot control the translation of proteins.
C. do not carry the complete genetic code in their nuclei.
D. do not need the proteins that are specified by certain genes.

Have a wonderful day! :D</span>
olchik [2.2K]4 years ago
4 0

Specialized cells regulate the expression of genes because they do not need the proteins that are specified by certain genes.

I researched on internet.

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The femoral artery becomes the popliteal artery after passing the inguinal ligament.
Digiron [165]

The femoral artery becomes the popliteal artery after passing the adductor hiatus.

<h3>What is adductor hiatus?</h3>

The femoral artery and vein travel from the thigh's adductor canal to the popliteal fossa through the adductor hiatus (AH), which is an opening in the muscle's aponeurotic distal attachment.

The femoral artery, vein, and femoral nerve branches are all located within the canal.

The area containing the femoral artery and vein below the femoral triangle is known as the subsartorial canal or adductor canal. Hunter's canal got its name because he was the first to explain how to expose and ligate the femoral artery to treat popliteal aneurysms.

To know more about adductor hiatus you may visit the link:

brainly.com/question/24182056

#SPJ4

8 0
1 year ago
In Wakanda, in a population in Hardy-Weinberg equilibrium, the frequency of the single recessive allele controlling vibranium as
AnnyKZ [126]

Answer:

32%

Explanation:

Hardy–Weinberg equilibrium is also known as Hardy–Weinberg law. The idea of Hardy–Weinberg equilibrium is about the frequency of alleles in a population. The frequency of an allele in the population will always remain the same in a population if that population is not influenced by any evolutionary consequences.

Hardy–Weinberg equilibrium binomial expression formula is p2+2pq+q2=1. Suppose the frequency of recessive allele = q.

and another normal allele is = p

Here Q = 0.2 so P will be 1- Q or 0.8

By Hardy–Weinberg equation p2+2pq+q2=1, Here 2pq denotes the frequency of recessive allele, so 2pq = 2 × 0.2 × 0.8 = 0.32, if converted into percentage it will be 32%.

6 0
3 years ago
Why dominant traits may not necssairly be more common in a population
nataly862011 [7]
This isn't always the case and there is no reason it should be .Whether or not a trait is common has to do with how many copies of that gene version (or allele) are in the population. It has little or nothing to do with whether the trait is dominant or recessive. Let's take eye color as an example.
8 0
4 years ago
Can somebody help me pleaseee ASAP! 15 points
inessss [21]

all that dang thats a lot but i will do the best i can

8 0
4 years ago
What did Wegener use to support his theory of continental drift?
asambeis [7]
The first argument Wegener put forward in support of his theory was that the continents seemed to fit together like the pieces of a jigsaw puzzle. This relationship is apparent from a map, but the exactness of the match improves if the underwater continental shelves are compared. The true edges of South America and Africa, for example, fit together to a high degree of precision, allowing for millions of years of erosion.
Wegener's second argument was more complex. He traveled the world and charted the locations and orientation of glacial till deposits. These deposits are the alluvial remnant of a glacier's progress across the landscape, and they remain long after the glacier has melted away. By plotting out the latitudes of ancient till deposits, Wegener was able to demonstrate that, for his evidence to be consistent with unmoving continents, much of the world would have had to be covered in ice sheets in the relatively recent past, even in the tropics. He argued that this was evidence that the tropical continents had once been at higher latitudes.
3 0
3 years ago
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