Question

In Wakanda, in a population in Hardy-Weinberg equilibrium, the frequency of the single recessive allele controlling vibranium assimilation, which affects superhuman abilities, is 0.2. What is the percentage of the population that is heterozygous for this allele

Answer 1

Answer:

32%

Explanation:

Hardy–Weinberg equilibrium is also known as Hardy–Weinberg law. The idea of Hardy–Weinberg equilibrium is about the frequency of alleles in a population. The frequency of an allele in the population will always remain the same in a population if that population is not influenced by any evolutionary consequences.

Hardy–Weinberg equilibrium binomial expression formula is p2+2pq+q2=1. Suppose the frequency of recessive allele = q.

and another normal allele is = p

Here Q = 0.2 so P will be 1- Q or 0.8

By Hardy–Weinberg equation p2+2pq+q2=1, Here 2pq denotes the frequency of recessive allele, so 2pq = 2 × 0.2 × 0.8 = 0.32, if converted into percentage it will be 32%.