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kow [346]
3 years ago
6

A retailer at an outdoor market sold 5 dresses at $36.95 each. He sold 2 more at $41.99 each and 3 at $38.95 each. He also sold

one $52 dress at 40% off. He pays the market 20% of sales.How much did he take in from sales after paying the market?
Mathematics
2 answers:
ss7ja [257]3 years ago
6 0
5*36.95= $<span>184.75
2*42.99= $</span><span>85.98
3*38.95= $</span>116.85
1*52*0.6=$<span>31.20    (40% off) multiply by 0.6)

Add 184.75+85.98+116.85+31.20=$</span>418.78 - 20% thus: 418.78*.8= $ <span>335.024</span>
miss Akunina [59]3 years ago
3 0

Answer:

$333.424 will retailer will take back his home.

Step-by-step explanation:

Total price of 5 dresses sold at $36.95 each = 5 × $36.95 = $184.75

Total price of 2 dresses sold at $41.99 each = 2 × $41.99 = $83.98

Total price of 3 dresses sold at $38.95 each = 3 × $38.95 = $116.85

Total price of 1 dress of  $38.95 each sold at 40% off:

\$52-40\%\times \$52=\$31.2

Total amount from the selling of all dresses = T

T = $184.75+$83.98+$116.85+$31.2=$416.78

Percent of sells to paid to market = 20%

Amount left with retailer after paying to the market = A

A=T-20\% \times T=\$416.78-\frac{20}{100}\times \$416.78=\$ 333.424

$333.424 will retailer will take back his home.

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3 years ago
Rhombus EFGH is shown. What is the measure of ∠HGJ?
MaRussiya [10]

Answer:

∠HGJ = 35°

Step-by-step explanation:

Although the question is somewhat incomplete, I have tried to reconstruct the question as much as possible to aid understanding (attached is the pictorial representation of the rhombus).

Firstly, it is important to note that rhombuses are parallelograms which have all sides equal and whose diagonals are perpendicular to each other. In addition to this, their diagonals bisect one other.

Mathematically, |EF| = |FG| = |GH| = |HE|

Another property which rhombuses have is that their opposite angles are equal.

Mathematically, ∠E = ∠G, ∠H = ∠F

The adjacent angles in a rhombus are supplementary. This means that the sum of angles closest to each other is 180°.

Mathematically, ∠E + ∠F = 180°, ∠F + ∠G = 180°, ∠G + ∠H = 180°,

∠H + ∠E = 180°

The question gave us ∠GHE and asked us to find ∠HGJ (denoted as θ in the picture attached). Note that ∠GHE means ∠H. That is, ∠GHE ⇒ ∠H

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∠GHE + ∠FGH ⇒ 110° + ∠FGH = 180° ⇒ ∠FGH = 180° - 110°

∠FGH or ∠G = 70°

To calculate for ∠HGJ, we divide ∠FGH by 2, we have:

∠HGJ = ∠FGH ÷ 2 = 70° ÷ 2

∠HGJ = 35°

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