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devlian [24]
3 years ago
11

(a+b)^2–(b+c)^2 as a product of two polynomials

Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0

Hey there!!

In order to solve this problem, we will need to use the identity a² - b²

∴ a² - b² = ( a + b ) ( a - b )

According to the question,

a = a + b

b = b + c

( a + b )² - ( b + c )²

... ( a + b + b + c ) ( a + b - b - c )

... ( a + 2b + c ) ( a - c )

Now, we will need to solve this using distributive property.

Distribute a with a , 2b , c and distribute -c with a , 2b and c and then combine all the like terms.

... ( a² + 2ab + ac ) + ( -ac - 2bc - c² )

... ( a² + 2ab + ac - ac - 2bc - c² )

... ( a² + 2ab - bc - c² )

Hope my answer helps!!

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Answer:

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Step-by-step explanation:

Let

A \to Amount

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Given

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Required

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To do this, we make use of:

A(t) = A(0) * e^{kt}

A(5)  = 160 implies that:

160 = 200 * e^{k*5}

Divide both sides by 200

0.80 = e^{k*5}

Take natural logarithm of both sides

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So, we have:

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Divide by 5

k = -0.045

So, the function is:

A(t) = A(0) * e^{kt}

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The amount after 10 minutes is:

A(10) = 200 * e^{-0.045*10}

A(10) = 200 * e^{-0.45}

A(10) = 127.53

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