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vodomira [7]
4 years ago
14

Can someone help me please

Mathematics
1 answer:
Novay_Z [31]4 years ago
6 0

Answer:

B.  x  = -5 +/- √30.

Step-by-step explanation:

2x^2 + 20x = 10

2(x^2 + 10x) = 10

2[ (x + 5)^2 - 25 ] =10

2(x + 5)^2 - 50 = 10

2(x + 5)^2 = 60

(x + 5)^2 = 30

x + 5 =  +/- √30

x  = -5 +/- √30.

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The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

                                               = 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

7 0
4 years ago
Read 2 more answers
Limit question thing plz help me
Sphinxa [80]

Answer:

The limit does not exist

Step-by-step explanation

For this question you have to look at the function and see what y value does it approach as it gets closer and closer to x =2, from the left side it looks like it approaces 4 and from the left side it looks like it's approaching 1, since the limits from the left and right sides are not the same, the limit does not exist

5 0
3 years ago
JK is tangent to a circle with centre H as shown below. What is HK ?<br> 8 mi<br> 15 mi
sashaice [31]

Given:

JK is tangent to a circle with center H

To find:

The length of HK.

Solution:

The image is attached below.

JK = 8 mi, HJ = 15 mi

JK is tangent to a circle.

The tangent is always perpendicular to the radius.

Therefore, m∠J = 90°

Using Pythagoras theorem:

HK² = JK² + HJ²

HK² = 8² + 15²

HK² = 64 + 225

HK² = 289

HK² = 17²

Taking square root on both sides.

HK = 17

The length of HK is 17 mi.

3 0
3 years ago
Fine the sum of the first 17 terms of the arithmetic sequence 10,14,18,22,26
Natasha2012 [34]
10,14,18,22,26,30,34,38,42,46,50,54,58,62,66,70,74
7 0
4 years ago
Jane and John had an equal number of flowers. Jane made bouquets with 7 flowers each, while John made bouquets with 9 flowers ea
kolbaska11 [484]

Answer:

63

Step-by-step explanation:

The least common multiple of 7 and 9 is 63

6 0
2 years ago
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