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kiruha [24]
3 years ago
14

May anyone give me an example of a independent and an dependent probability word problem about food?

Mathematics
2 answers:
PtichkaEL [24]3 years ago
8 0
Bob wants to see which shoes he can give away at a randm pick from a jar

dependent
if he has 20 pairs of shoes and he has 10 friends, what is the probability that at least 1 freiend will get a matching pair if they do not replace the shoe after they picked it

dependent
if he has 20 pairs of shoes and he has 10 friends, what is the probability that at least 1 freiend will get a matching pair if they do not replace the shoe after they picked it and flip a heads on a coin

jonny [76]3 years ago
8 0
Here's a dependent, If you have 8 coins in a bag and 3 are unfair in that have a 60% chance of coming up heads when flipped (the rest are fair). You randomly choose one coin from the bag and flip it 2 times. What's the percent probability of flipping 2 heads?
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Find the value of x.
kiruha [24]
X=5
x=20
x=142
:))))))))
5 0
3 years ago
Read 2 more answers
A metal plate, with constant density 5 g/cm^2, has a shape bounded by the curbe y = x^2 and the x-axis, with 0<= x <= 3 an
nignag [31]

Answer:

a) 45 g

b) greater (make the graph youself on desmos or something)

c) 9/4

Step-by-step explanation:

area = integral 0 to 3 of x^2 dx = [1/3x^3] 0 to 3 = 9

mass = density * area = 5 * 9 = 45 grams

area = y*deltax = x^2*deltax

x = integral 0 to 3 of 5x^3 dx / mass = (405/4) / 45 = 9/4

4 0
3 years ago
What will be the value of
madreJ [45]

The expression as given doesn't make much sense. I think you're trying to describe an infinitely nested radical. We can express this recursively by

\begin{cases}a_1=\sqrt{42}\\a_n=\sqrt{42+a_{n-1}}\end{cases}

Then you want to know the value of

\displaystyle\lim_{n\to\infty}a_n

if it exists.

To show the limit exists and that a_n converges to some limit, we can try showing that the sequence is bounded and monotonic.

Boundedness: It's true that a_1=\sqrt{42}\le\sqrt{49}=7. Suppose a_k\le 7. Then a_{k+1}=\sqrt{42+a_k}\le\sqrt{42+7}=7. So by induction, a_n is bounded above by 7 for all n.

Monontonicity: We have a_1=\sqrt{42} and a_2=\sqrt{42+\sqrt{42}}. It should be quite clear that a_2>a_1. Suppose a_k>a_{k-1}. Then a_{k+1}=\sqrt{42+a_k}>\sqrt{42+a_{k-1}}=a_k. So by induction, a_n is monotonically increasing.

Then because a_n is bounded above and strictly increasing, the limit exists. Call it L. Now,

\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}a_{n-1}=L

\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}\sqrt{42+a_{n-1}}=\sqrt{42+\lim_{n\to\infty}a_{n-1}}

\implies L=\sqrt{42+L}

Solve for L:

L^2=42+L\implies L^2-L-42=(L-7)(L+6)=0\implies L=7

We omit L=-6 because our analysis above showed that L must be positive.

So the value of the infinitely nested radical is 7.

4 0
3 years ago
Negative six and one third plus twenty over three
nydimaria [60]

Answer:

1/3

Step-by-step explanation:

-6+(-1/3)= -19/3

-19/3 + 20/3 = 1/3

6 0
4 years ago
How do you solve this?
Artyom0805 [142]

Triginometry. Which side do you want to solve for?

6 0
3 years ago
Read 2 more answers
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