Answer:
Explanation:
Given a class C IP address
195.1.1.0
Existing mask is 255.255.255.0
We want to have 12 hosts on 10 subnets.
A class C address has 8 bits of the host which will give, n=8
2ⁿ - 2 = 254 hosts
Current mask= 255.255.255.0
Bits needs for 10 subnets
2ⁿ = 10, n = 4bits
n = 4 = 2⁴ = 16 possible subnets
Now, bit needed for 12host, n =4bits
2⁴-2 = 14 possible host,
Total of 8 bits needed so therefore we can use as 4bits for the subnet.
So we could have
4 bit subnet and 4 bits hosts
11110000 = 240decimals
Final possible masks is
255.255.255.240
