Answer:
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
Step-by-step explanation:
We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.
Firstly, Let X = women's gestation period
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= average gestation period = 270 days
= standard deviation = 9 days
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X
261)
P(X < 279) = P(
<
) = P(Z < 1) = 0.84134
P(X
261) = P(
) = P(Z
-1) = 1 - P(Z < 1)
= 1 - 0.84134 = 0.15866
<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>
Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
The answer is 54,550 more.
Before we can make sure that E is correct, we need to make the denominator is equal with questions and the choices or convert into decimal.
2/3 = 0.66
1/3=0.33
1/5=0.2
2/6=1/3 = 0.33
1/2 = 0.5
7/10 = 0.7
7/9 = 0.77
The question is :
2/3 < x < 7/9
0.66 < x < 0.77
We need to divide into 2 parts :
0.66 < x
x < 0.77
So we need to find the answer that x is greater that 0.66 and we got 7/10. And 7/10 is less than 7/9.
Hope this helps. Please ask if you don't understand.
Answer:
92511cm3
Step-by-step explanation: