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2 years ago

Need an explanation on number 44 to why E is correct

Mathematics

1 answer:

aliina [53]2 years ago

6 0

Before we can make sure that E is correct, we need to make the denominator is equal with questions and the choices or convert into decimal.

2/3 = 0.66

1/3=0.33

1/5=0.2

2/6=1/3 = 0.33

1/2 = 0.5

7/10 = 0.7

7/9 = 0.77

The question is :

2/3 < x < 7/9

0.66 < x < 0.77

We need to divide into 2 parts :

0.66 < x

x < 0.77

So we need to find the answer that x is greater that 0.66 and we got 7/10. And 7/10 is less than 7/9.

Hope this helps. Please ask if you don't understand.

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X2 - 49 = 0 solve for x

Bogdan [553]

x^2 - 49 = 0

Add 49 to both sides:

x^2 = 49

Take the square root of both sides:

X = 7

8 0

2 years ago

Marcie cooked dinner for herself. The original recipe has a serving size of 4 and requires four and four fifths pounds of chicke

Margarita [4]

Answer:

1.2 pounds of chicken per serving.

Step-by-step explanation:

4 and 4/5 of pounds of chicken for serving of 4.

We can also write this as 4.8 pounds of chicken.

To find how much pound of chicken will be needed for a single serving we have to divide 4.8 by 4.

$\frac{4.8}{4} = 1.2 \: pounds \: of \: chicken$

If this answer helped you, give this answer a heart and rate it.

Thanks!

7 0

1 year ago

Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe

ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for $n\geq 78$

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: $\sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4$

For n=1: $\sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4$

From this point we will assume that $n\geq 2$

As we can see, $\sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4$ and $(4n)^4=256n^4$ . Then,

$\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4$

Now, we will use the formula for the sum of the first 4th powers:

$\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}$

Therefore:

$\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0$

and, because $n \geq 0$ ,

$465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1$

Observe that, because $n \geq 2$ and is an integer,

$n^2(465n-6n^2-10)\geq -1 \iff 465n-6n^2-10 \geq 0 \iff n(465-6n) \geq 10\\\iff 465-6n \geq 0 \iff n \leq \frac{465}{6}=\frac{155}{2}=77.5$

In concusion, the statement is true if and only if n is a non negative integer such that $n\leq 77$

So, 78 is the smallest value of n that does not satisfy the inequality.

Note: If you compute $(4n)^4- \sum^{n}_{i=0} (2i)^4$ for 77 and 78 you will obtain:

$(4n)^4- \sum^{n}_{i=0} (2i)^4=53810064$

$(4n)^4- \sum^{n}_{i=0} (2i)^4=-61754992$

7 0

2 years ago

Help how many questions did you answer correctly

Lady bird [3.3K]

Answer:

450

Step-by-step explanation:

you divide 90 by 20 and times in by 100

4 0

2 years ago

Read 2 more answers

Solve the equation. Check your solution.

VladimirAG [237]

-5x/6 + 1=7/18
lowest common multiple=18
-15x+18=7
-15x=7-18
-15x=-11
x=-11/-15=11/15

The solution set is [11/15]

we check it out.
-5(11/15) /6 + 1 =7/18
(-55/15) / 6 +1=7/18
-55/90 + 1=7/18
(-55+90) /90=7/18
35/90=7/18
7/18=7/18

5 0

2 years ago