3 years ago

Given h(f)=-2(t+5)^2 +4, find h(-8)

Mathematics

2 answers:

erastova [34]3 years ago

8 0

Answer:

h(-8) = 22

Step-by-step explanation:

Plug -8 in for t and simplify...

h(-8) = 2(-8 + 5)² + 4

h(-8) = 2(-3)² + 4

h(-8) = 2(9) + 4

h(-8) = 18 + 4

h(-8) = 22

kogti [31]3 years ago

7 0

Answer:

Step-by-step explanation:

Given h(f)=-2(t+5)^2 +4

There is an intermediate step which is

h(f) = -2(f + 5)^2 + 4

h(-8) = -2(-8 + 5)^2 + 4

h(-8) = -2(-3)^2 + 4

h(-8) = -2(9) + 4

h(-8) = -18 + 4

h(-8) = - 14

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