So assuming that the total =27
r+b=27
r=-5+3b
r=3b-5
subsitute 3b-5 for r in first equation
3b-5+b=27
4b-5=27
add 5
4b=32
divide by 4
b=8
subsitute
b+r=27
8+r=27
subtracct 8
r=19
red=19
blue=8
answer
(x+7)^2 + (y-4)^2 = 64
set up equation
the equation of a circle is (x - h)^2 + (y - k)^2 = r^2
where h is the center x coordinate and k is the center y coordinate
values
from the point (-7,4) we know that h = -7 and k = 4
since the radius is 8, r^2 = 8^2 = 64
plug in values
now that we have all the values, we plug them into (x - h)^2 + (y - k)^2 = r^2
(x - h)^2 + (y - k)^2 = r^2
(x - (-7))^2 + (y-4)^2 = 64
(x+7)^2 + (y-4)^2 = 64
Answer:
√10z^3(z - 1)(z + 1).
Step-by-step explanation:
The GCF is √10z* z^2
= √10z^3
So factoring we get
√10z^3(z^2 - 1) The expression in brackets is difference of 2 squares so:
= √10z^3(z - 1)(z + 1)