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Bas_tet [7]
3 years ago
7

Given sin x=0.3 , what is cos x ?

Mathematics
2 answers:
blsea [12.9K]3 years ago
7 0
Cos x = sqrt( 100 - 9) / 10 
<span>= 0.9539392014</span><span>sin x = 0.3 = 3/10
</span>
shusha [124]3 years ago
7 0

Answer:  The value of \cos x is 0.95.

Step-by-step explanation:  Given that, for an angle x,

\sin x=0.3.

We are given to find the value of \cos x.

We will be using the following trigonometric identity:

\cos^2x+\sin^2x=1.

We have

\cos^2x+\sin^2x=1\\\\\Rightarrow \cos^2x=1-\sin^2x\\\\\Rightarrow \cos x=\sqrt{1-\sin^2x}\\\\\Rightarrow \cos x=\sqrt{1-(0.3)^2}\\\\\Rightarrow \cos x=\sqrt{1-0.09}\\\\\Rightarrow \cos x=\sqrt{0.91}\\\\\Rightarrow \cos x=0.95.

Thus, the value of \cos x is 0.95.

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The square ABCD has side length 20 cm,
bogdanovich [222]

Answer:

AE=22.4

Step-by-step explanation:

BE is 1/2 of BC

BC is 20 cm                 All sides of a square are equal

BE = 1/2 BC                  Property of a midpoint.

BE = 10

Now just use Pythagorus

AB^2 + BE^2 = AE^2

AE^2 = 20^2 + 10^2   Perform the sqrs

AE^2 = 400 + 100      Add the terms

AE^2 = 500                Take the square root of both sides

√AE^2 = √500

AE = 22.36

AE ≈ 22.4

6 0
3 years ago
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erik [133]

let's firstly convert the mixed fractions to improper fractions and then divide.

\bf \stackrel{mixed}{17\frac{13}{18}}\implies \cfrac{17\cdot 18 +13}{18}\implies \stackrel{improper}{\cfrac{319}{18}}~\hfill \stackrel{mixed}{2\frac{7}{9}}\implies \cfrac{2\cdot 9+7}{9}\implies \stackrel{improper}{\cfrac{25}{9}} \\\\[-0.35em] ~\dotfill

\bf \cfrac{319}{18}\div \cfrac{25}{9}\implies \cfrac{319}{\underset{2}{~~\begin{matrix} 18 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{\stackrel{1}{~~\begin{matrix} 9 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{25}\implies \cfrac{319}{50}\implies 6\frac{19}{50}

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Dmitrij [34]

Answer: You have 1.65 will be you answer

Step-by-step explanation:

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I think the answer is 7/8
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