PART 1If I have graph f(x) then graph f(x + 1/3) would translate the graph 1/3 to the left.
For example, I have f(x) = x².Then
f(x + 1/3) = (x + 1/3)²
I draw the graph of f(x) = x² and the graph of f(x) = (x + 1/3)² on cartesian plane to know what's the difference between them.
PART 2If I have graph f(x) then graph f(x) + 1/3 would translate the graph 1/3 upper.
For example, I have f(x) = x².Then
f(x) + 1/3 = x² + 1/3
I draw the graph of f(x) = x² and the graph of f(x) = x² + 1/3 on cartesian plane to know what's the difference between them.
SUMMARY
f(x+1/3) ⇒⇒ <span>f(x) is translated 1/3 units left.
f(x) + 1/3 </span>⇒⇒ <span>f(x) is translated 1/3 units up.</span>
Answer:
810 min
Step-by-step explanation:
5 miles for 45 min
90 miles for x min
x = (90*45)/5
x= 810 min = 13.5 hours
Answer:
B. -8
Step-by-step explanation:
F(x) = 2x
F(-4) = 2(-4) = -8
Answer:
Marginal revenue = R'(Q) = -0.6 Q + 221
Average revenue = -0.3 Q + 221
Step-by-step explanation:
As per the question,
Functions associated with the demand function P= -0.3 Q + 221, where Q is the demand.
Now,
As we know that the,
Marginal revenue is the derivative of the revenue function, R(x), which is equals the number of items sold,
Therefore,
R(Q) = Q × ( -0.3Q + 221) = -0.3 Q² + 221 Q
∴ Marginal revenue = R'(Q) = -0.6 Q + 221
Now,
Average revenue (AR) is defined as the ratio of the total revenue by the number of units sold that is revenue per unit of output sold.

Where Total Revenue (TR) equals quantity of output multiplied by price per unit.
TR = Price (P) × Total output (Q) = (-0.3Q + 221) × Q = -0.3 Q² + 221 Q


∴ Average revenue = -0.3Q + 221