For lines to be perpendicular their slopes must be negative reciprocals of one another, mathematically:
m1*m2=-1, and in this case:
-m/4=-1
-m=-4
m=4, so the slope of the perpendicular line is 4 so we have thus far:
y=4x+b, using point (-4,3) we can solve for the y-intercept, "b"
3=4(-4)+b
3=-16+b
19=b, so our line is:
y=4x+19
Answer:
x=40
Step-by-step explanation:
Angle Formed by Two Secants= 1/2(DIFFERENCE of Intercepted Arcs)
x = 1/2(120-40)
x = 1/2(80)
x = 40
Answer:
(3y - 2)(2y - 7)
Step-by-step explanation:
To factorise the quadratic
Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term
Product = 6 × 14 = 84 and sum = - 25
The required factors are - 4 and - 21
Use these factors to split the y- term
6y² - 4y - 21y + 14 ( factor the first/second and third/fourth terms )
2y(3y - 2) - 7(3y - 2) ← factor out (3y - 2) from each term
= (3y - 2)(2y - 7) ← in factored form
Answer:
Step-by-step explanation:
eq. of line parallel to AB is y=2x+a
if it passes through (3,-2) then
-2=2×3+a
a=-2-6=-8
y=2x-8