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3 years ago

14

What is the simplified version of sixth root of 27

1 answer:

vovangra [49]3 years ago

7 0

Exact Form:
√
3

Decimal Form:
1.73205080

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A circle's radius is increased by 10%. By what percentage does its area increase

Vladimir79 [104]

Answer: 21%

Explanation: Let the radius of the circle =R therefore area of the circle = [pi][R * R]
Radius of the circle after 10% increase =R+10% of R=R+R/10=11R/10
Therefore AREA of the circle with radius 11R/10 =[pi][11R/10*11R/10]=[pi][121R*R/100] Hence INCREASE in the AREA of the circle=[pi][121R*R/100]-[pi][R*R] =[pi] [R*R][121/100-1] =[pi][R*R][121-100]/100=[pi][R*R][21]/100 THEREFORE % increase in the area of the circle=[pi][R*R][21/100]/[pi][R*R] whole multiplied by 100=21 HENCE increase in the area of the circle =21% NOTE : pi is a constant whose value=22/7

4 0

3 years ago

Each endpoint of a side of a polygon is

lakkis [162]

The endpoint of a side of a polygon is called a___ the answer is B

3 0

3 years ago

Read 2 more answers

Which of the following is equivalent to4−(−5∗9−1)÷2+(5)2−7?

Gala2k [10]

Answer:

-20

Step-by-step explanation:

Follow the PEDMAS order (from top to bottom):

Parentheses

Exponents

Division and Multiplication

Addition and Subtraction

(-5 × 9 - 1) ÷ 2 + (5)2 - 7

(-45 - 1) ÷ 2 + 10 - 7

-46 ÷ 2 + 10 - 7

-23 + 10 - 7

-13 - 7

-20

8 0

3 years ago

Read 2 more answers

In circle N with m<br> See diagram below

Alex777 [14]

Answer:

$113.10$

Step-by-step explanation:

The area of a sector with measure $\theta$ and radius $r$ is given by $A_{sec}=r^2\pi\cdot \frac{\theta}{360^{\circ}}$ .

What we're given:

$r$ of 12
$\theta$ of $90^{\circ}$

Substituting given values, we get:

$A_{sec}=12^2\pi\cdot \frac{90}{360},\\\\A_{sec}=144\pi\cdot \frac{1}{4},\\\\A_{sec}\approx \boxed{113.10}$

8 0

3 years ago

What is the factored form of the expression?<br><br> d^2 = 36d + 324

Veseljchak [2.6K]

Answer:

$(x-43.45)(x+7.45)=0$

Step-by-step explanation:

We have the quadratic equation $d^{2}=36d+324$ i.e. $d^{2}-36d-324=0$

As, the roots of the quadratic equation $ax^{2}+bx+c=0$ are given by $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ .

So, from the given equation, we have,

a = 1, b = -36 , c = -324.

Substituting the values in $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ , we get,

$x=\frac{36\pm \sqrt{(-36)^{2}-4\times 1\times (-324)}}{2\times 1}$

i.e. $x=\frac{36\pm \sqrt{1296+1296}}{2}$

i.e. $x=\frac{36\pm \sqrt{2592}}{2}$

i.e. $x=\frac{36\pm 50.9}{2}$

i.e. $x=\frac{36+50.9}{2}$ and $x=\frac{36-50.9}{2}$

i.e. $x=\frac{86.9}{2}$ and $x=\frac{-14.9}{2}$

i.e. x = 43.45 and x = -7.45

Thus, the roots of the equation are 43.45 and -7.45.

Hence, the factored form of the given expression will be $(x-43.45)(x+7.45)=0$

3 0

3 years ago