Answer:
b) far above average
Step-by-step explanation:
Normal Distribution
mean μ₀ = 76
Standard Deviation σ = 6
Values in Normal Distribution spread according to:
μ₀ + σ = 67.3 %
μ₀ + 2*σ = 95.5 %
μ₀ + 3*σ = 99.7 %
Is relevant to explain that these values spread simmetrically, having as symmetry axis the mean (That is: when we see μ₀ + 2*σ, that means that from μ₀, we will find half of values under the mean and the other half above)
To examine the value 89, scored in the last game we will look for our paticular case values obtained from previuos conditions
That implies:
μ₀ + σ = 76 ± 0,5σ = 76 ± 3 upper limit 79
μ₀ + 2σ = 76 ± σ = 76 ± 6 upper lmit 82
μ₀ + 3σ = 76 ± 1.5 σ = 76 ± 9 upper limit 85
We should expect most of the values between the above intervals, the value " 89 " is bigger than 85, the point limit of the 99.7 % of all values, so we should conclude that 89 is far above average ( μ₀ )
