Question

Which of the following are solutions to the equation sinx cosx = (sqrt of 3)/4? Check all that apply.

Answer 1

$\sin x \cos x = \dfrac{\sqrt 3}{4}$

$2 \sin x \cos x = \dfrac{\sqrt 3}{2}$

$\sin 2x = \sin \frac \pi 3$

$2x = \frac \pi 3 + 2 \pi n \textrm{ or } 2x = (\pi - \frac \pi 3) + 2 \pi n \quad \textrm{integer } n$

$x = \frac \pi 6 + \pi n \textrm{ or } x = \frac \pi 3 + \pi n$

Choices A and C