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4 years ago

If the measure of angle DCF = 34 and the measure of angle DEF = 90, find the measure of angle CDE.

Mathematics

1 answer:

spayn [35]4 years ago

3 0

Answer:

118

Step-by-step explanation:

Triangle CDE contains angles CDE, DCR and DER

Angles DCR=17 and DER=45 because in a kite, the diagonal on the line of symmetry bisects the angles and 34-2=17 90/2=45

The angles in a triangle add up to 180 and 180-17-45=118, meaning angle DER=118

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Find the distance between the two points. (5,-3) (-4,7)

STatiana [176]

Answer:

-9.4

Step-by-step explanation:

8 0

3 years ago

A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

The null hypothesis is accepted .

Assume the population variances are approximately the same

Step-by-step explanation:

Explanation:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

The first sample size 'n₁'= 20

mean of the first sample 'x₁⁻'= 17.53 pounds

standard deviation of first sample S₁ = 3.2 pounds

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

The second sample size n₂ = 24

mean of the second sample "x₂⁻"= 14.89 pounds

standard deviation of second sample S₂ = 2.7 pounds

Null hypothesis:-H₀: The Population Variance are approximately same

Alternatively hypothesis: H₁:The Population Variance are approximately same

Level of significance ∝ =0.05

Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42

Test statistic :-

$t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

where $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

substitute values and we get S² = 40.988

$t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$

t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

Conclusion:-

The null hypothesis is accepted

Assume the population variances are approximately the same.

6 0

3 years ago

So,some please help!

Leni [432]

4.6 is the correct answer. Hope I helped:)

5 0

3 years ago

Read 2 more answers

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True [87]

Answer:5in

Step-by-step explanation:

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25=c^2

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5 0

1 year ago

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Alenkasestr [34]

Answer:

$\boxed{6x^2-35x+36}$