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4 years ago

If the measure of angle DCF = 34 and the measure of angle DEF = 90, find the measure of angle CDE.

Mathematics

1 answer:

spayn [35]4 years ago

3 0

Answer:

118

Step-by-step explanation:

Triangle CDE contains angles CDE, DCR and DER

Angles DCR=17 and DER=45 because in a kite, the diagonal on the line of symmetry bisects the angles and 34-2=17 90/2=45

The angles in a triangle add up to 180 and 180-17-45=118, meaning angle DER=118

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PLEASE HELP!! within the interval notation of [-3,-2) the function below is…

kkurt [141]

Answer: increasing

Step-by-step explanation: The slope of the graph is positive.

7 0

3 years ago

Help! How would I solve this trig identity?

NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$

Now we can use the identity:

sin²(x) + cos²(x) = 1

$1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1$

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

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7 0

2 years ago

What's x+3 = 9-4? Please help please help

erica [24]

X + 3 = 9-4

First simplify the right side.

9-4 = 5

Now you have x + 3 = 5

Now subtract 3 from both sides:

X = 2

Answer: x = 2

5 0

3 years ago

Read 2 more answers

You don't have to do all of them

vova2212 [387]

Answer: lol your using canvas

1. 63

2. D

3. B

4. A

Sorry for the bland explinations havin a bad day.

Step-by-step explanation:

1. The way we solve this is by adding the degrees 72 and 45. then we subtract it by 180. this is because in all triangles the angles always add up to 180 degrees.

2. Like question one what set of angles measures to 180 degrees.

3. The sides of a triangle should define the angle measurements. you can also see if its a triangle if the numbers are continues like 3,4,5 or in this case 4,5,6

4. like in questions 1 and 2 the angles of a triangle has to equal 180 degrees so 60 times 3 is 180 so each angle would have to be 60 degrees.

7 0

3 years ago

I beg for someone. I need a maximum, minimum, domain, and range of polynomial:

elena-s [515]

Answer:

domain: all real numbers, (-∞, ∞)
range: all real numbers, (-∞, ∞)
maximum: +∞
minimum: -∞

Step-by-step explanation:

The function is an odd-degree polynomial. The domain and range of any odd-degree polynomial is (-∞, +∞). It has no finite maximum or minimum.

There are 3 local maxima, and 3 local minima. The ones that are non-zero are irrational. Those are about -150.018, -580.455, and 578.545. If you're seriously expected to solve for these values, no doubt you have been given a method for doing so. Use that method.

These local extreme values are reported by the Desmos on-line graphing calculator.

3 0

4 years ago