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3 years ago

Please help me !!!

Mathematics

2 answers:

Pie3 years ago

8 0

3. 5mn ( 2m + 6n + 1 )
4. 4a^3b^2c ( 18a^2b - 8c )
5. (X-15)(X+15)
6. -4(y-4.5)(y+4.5)
8. 2X(X-10)(X+10)
i am not sure if no. 8 is right

FromTheMoon [43]3 years ago

4 0

$1)~28c-12=4(7c-3)\\\\
2)~x^2y+x=x(xy+1)\\\\
3)~10m^2n+30mn^2+5mn=5mn(2m+6n+1)\\\\
4)~72a^5b^3c-32a^3b^2c^2=8a^3b^2c(9a^2b-4c)\\\\
5)~x^2-225=(x-15)(x+15)\\\\
6)~81-4y^2=(9-2y)(9+2y)\\\\
7)~9k^4-25=(3k^2-5)(3k^2+5)\\\\
8)~2x^3-200x=2x(x^2-100)=2x(x-10)(x+10)\\\\
9)~72y^4-18y^2=18y^2(4y^2-1)=18y^2(2y-1)(2y+1)\\\\
10)~49x^3-xy^2=x(49x^2-y^2)=x(7x-y)(7x+y)$

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3 years ago

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Answer=B

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g(x)=-4x-3.

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salantis [7]

Answer:

Frank can put 5 cubes in the box.

Step-by-step explanation:

Formula:

Mass = Volume × density.

1 cubic centimetre = 0.001 liter= 1 millilitre

Given that,

Frank purchase a new ice box having 2 kg capacity.

So,the mass of the cubes is 2 kg.

Each ice cubes measured 3.5 cm by 3.5 cm by 3.5 cm.

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The volume of a each ice cubes is = $3.5^3$ cm³

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The mass of each cubes are

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According to the problem,

39.18775x=2,000

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Frank can put 5 cubes in the box.

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