Answer:
A8 = 66 [8th term]
Step-by-step explanation:
Given the explicit arithmetic sequence An = -14 + 10n → -4 + 10(n-1)
To find the 8th term. An nth term is where n is n in the sequence. So substitute 8 for n, and simplify.
So A8 = -4 + 10(8-1) → -4 + 10(7) → -4 + 70 → 70 - 4 → 66.
1. If you have 1 first then... 1,2,3,4 - 1,3,2,4 - 1,2,4,3 - 1,3,4,2 - 1,4,3,2 - 1,4,2,3
2. If you have 2 first the.... 2,1,3,4,- 2,1,4,3 - 2,3,1,4 - 2,3,4,1 - 2,4,3,1- 2,4,1,3
3. And so one with 3,4
Hope this helps:)
Beaded braclets at 9 beads each
Then 156 beads = 156/9
17.333
But the answer is 17 braclets since she cannot make .333 of a braclet
Step-by-step explanation:
We khow the sum and the product of the zeroes of this quadratic polynomial
Here is a trick :
when we khow the sum S and the product P ofvtwo numbers we can find them by solving :
x²-Sx+p=0
here S= -8 and P=12
so:
x²+8x+12=0
Let Δ be the discrminant of this equation: a= 1 , b= 8 and c=12
Δ= 8²-4*12 =16
the zeros are:
(-8-4)/2= -6
(-8+4)/2 = -2
verify:
-6+(-2)= -8
-2*(-6)= 12
now the polynomial quadratic is:
(x+6)(x+2)
Answer:
Step-by-step explanation:
