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Evgen [1.6K]
3 years ago
10

A bag contains 5 blue marbles, 6 red marbles, and 9 green marbles. two marbles are drawn at random, one at a time and with out r

eplacement. what is the probability of selecting two red marbles
a) 9/20
b) 3/38
c) 1/19
d) 11/20
Mathematics
1 answer:
Bess [88]3 years ago
4 0
Your answer would be d) 11/20 knowing that there are in total 6 red marbles and you don't replace it so it would be 6+5=11 and 9+6+5= 20 so it would leave you with 11/20
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4 divided by 2 is equal to 2. A number that is 5 times that would be 10, which is 2x5.

Not sure if it's correct, but I hope it helps :)
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Manny used 8 tenth-size parts to model 8/10. Ana used fewer parts to model an equivalent fraction. How does the size of a part i
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Alrighty, let's think of it like this: You are trying to fill a box with a bunch of sports balls. You have tiny little golf balls, and you have giant bowling balls. You need to fill this same box all the way up.

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When it comes to your fraction, the box is the the number 8/10. That number will not change because we are not changing the size of the box.

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What is 16.92 x 8.4 how much is the sum.
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The Eco Pulse survey from the marketing communications firm Shelton Group asked individuals to indicate things they do that make
Bad White [126]

Answer:

a) There is a probability of 42% that the person will feel guilty for only one of those things.

b)There is a probability of 46% that a randomly selected person will not feel guilty for either of these reasons

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, for those people that will feel guilty about wasting food.

-Set B, for those people that will feel guilty about leaving lights on when not in a room.

The most important information is that there is a .12 probability that a randomly selected person will feel guilty for both of these reasons. It means that P(A \cap B) = .12.

The problem also states that there is a .39 probability that a randomly selected person will feel guilty about wasting food. It means that P(A) = 0.39. The probability of a person feeling guilty for only wasting food is PO(A) = .39-.12 = .27.

Also, there is a .27 probability that a randomly selected person will feel guilty about leaving lights on when not in a room. So, the probability of a person feeling guilty for only leaving the lights on is PO(B) = 0.27-0.12 = 0.15.

a) What is the probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room?

This is the probability that the person feels guilt for only one of those things, so:

P = PO(A) + PO(B) = 0.27 + 0.15 = 0.42 = 42%

b) What is the probability that a randomly selected person will not feel guilty for either of these reasons

The sum of all the probabilities is always 1. In this problem, we have the following probabilies

- The person will not feel guilty for either of these reasons: P

- The person will feel guilty for only one of those things:  PO(A) + PO(B) = 0.42

- The person will feel guilty for both reasons: PB = 0.12

So

`P + 0.42 + 0.12 = 1

P = 1-0.54

P = 0.46

There is a probability of 46% that a randomly selected person will not feel guilty for either of these reasons

4 0
3 years ago
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