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ollegr [7]
3 years ago
5

Find the simplified product:

Mathematics
2 answers:
ivann1987 [24]3 years ago
8 0
 I think we can do this by converting the radicals to exponents

the given expression =  2^1/3 * x^5/3 * 4 x^3
 = 4* 2^1/3 * x^14/3

the third option =  4 x^4 * 2^1/3  * x^2/3
                          = 4*2^1/3 * x^14/3 

so its the third option

Sunny_sXe [5.5K]3 years ago
4 0
Use:
\sqrt[n]{a}\cdot\sqrt[n]{b}=\sqrt[n]{a\cdot b}\\\\a^n\cdot a^m=a^{n+m}\\\\(a^n)^m=a^{n\cdot m}\\\\\sqrt[n]{a^n}=a


\sqrt[3]{2x^5}\cdot\sqrt[3]{64x^9}=\sqrt[3]{2x^5}\cdot\sqrt[3]{64}\cdot\sqrt[3]{x^9}\\\\=\sqrt{2x^5}\cdot4\cdot\sqrt[3]{x^9}=4\sqrt[3]{2x^5\cdot x^9}\\\\=4\sqrt[3]{2x^{5+9}}=4\sqrt[3]{2x^{14}}=4\sqrt[3]{2x^{2+12}}=4\sqrt[3]{2x^2x^{12}}\\\\=4\sqrt[3]{2x^2x^{4\cdot3}}=4\sqrt[3]{2x^2(x^4)^3}=4\sqrt[3]{2x^2}\cdot\sqrt[3]{(x^4)^3}\\\\=4\sqrt[3]{2x^2}\cdot x^4=\boxed{4x^4\sqrt[3]{2x^2}}
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Y=-2(x+7)(x-2) in standard form
aniked [119]

Step-by-step explanation:

-2(x2-2x+7x-14)

-2x2+4x-14x+28

-2x2-10x+28

4 0
3 years ago
wanda started walking along a path 27 seconds before Dave .Wanda walked at a constant rate of 3 feet per second. Dave walked alo
ValentinkaMS [17]

Answer:

54 seconds

Step-by-step explanation:

Wanda's walking rate = 3 ft/s

Wanda's head start = 27 s

Dave's walking rate= 4.5 ft/s

Let 't' be time after Dave started walking

The distance walked by Wanda and Dave, respectively, as a function of 't' are given by:

W(t) = (27+t)*3\\D(t) = 4.5*t

The instant 't' at which Dave catches up to Wanda (both distances walked are equal) is:

(27+t)*3= 4.5*t\\t=\frac{81}{1.5} \\t= 54\ s

7 0
3 years ago
For the triangle shown below, complete the following table.
dem82 [27]

Answer:

Step-by-step explanation:

In the given triangle

With reference angle A

perpendicular (P) = 3

hypotenuse (h) = 5

So  sin A = p/h = 3/5

and

With reference angle C

perpendicular (p)=  4

hypotenuse (h) = 5

Sin C = p/h = 4/5

hope it helps :)

3 0
3 years ago
-14 + 4n=-(1 +n) – 3
Jet001 [13]
N=2 ask me if you want an explanation.
7 0
3 years ago
Read 2 more answers
How far is the star away from the earth in AU?<br>.000302°<br>1AU​
andrew11 [14]

Answer:

  379,442 AU

Step-by-step explanation:

The angle bisector is the altitude of the triangle. The resulting right triangle has a distance of 1 AU opposite the 0.000151° angle. The length we're interested in is the hypotenuse of the triangle. The relevant trig relation is ...

  Sin = Opposite/Hypotenuse

  Hypotenuse = Opposite/Sin

  E-S distance = (1 AU)/sin(0.000151°) ≈ 379,442 AU

The star is about 379,442 AU from Earth.

6 0
3 years ago
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