Answer:
y= 11 + 1.50x. (y is the price, x is number of toppings)
Step-by-step explanation:
"Of the gravy" lol
To find the x-intercepts, you make f(x) = 0 and solve for x by setting each factor equal to 0.
0 = x(x + 1)(x - 5)(x - 7)
x = 0
x + 1 = 0
x = - 1
x - 5 = 0
x = 5
x - 7 = 0
x = 7
Your x-intercepts are x = - 1, 0, 5, 7
OR
There are x-intercepts at (- 1, 0), (0, 0), (5, 0), and (7, 0).
Answer: Do you know what the total degree is but if not an algebraic equation us 148-x = 26
Step-by-step explanation:
I assume it is the last one, 3n^2, because the degree is the exponent, which is two and the three is the coefficient, which is next to the variable, plus it is a monomial, so there is only one term, eliminating the first two, the third one is just reversed. Therefore, the answer should be the last one. Hope this helps. :)
Answer:
(a) The sample sizes are 6787.
(b) The sample sizes are 6666.
Step-by-step explanation:
(a)
The information provided is:
Confidence level = 98%
MOE = 0.02
n₁ = n₂ = n
Compute the sample sizes as follows:
Thus, the sample sizes are 6787.
(b)
Now it is provided that:
Compute the sample size as follows:
![n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B%28z_%7B%5Calpha%2F2%7D%29%5E%7B2%7D%5Ctimes%20%5B%5Chat%20p_%7B1%7D%281-%5Chat%20p_%7B1%7D%29%2B%5Chat%20p_%7B2%7D%281-%5Chat%20p_%7B2%7D%29%5D%7D%7BMOE%5E%7B2%7D%7D)
![=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2.33%5E%7B2%7D%5Ctimes%20%5B0.45%281-0.45%29%2B0.58%281-0.58%29%5D%7D%7B0.02%5E%7B2%7D%7D%5C%5C%5C%5C%3D6665.331975%5C%5C%5C%5C%5Capprox%206666)
Thus, the sample sizes are 6666.
