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3 years ago

Which rational number is one tick mark to the right of Negative 6 Over 4 on the number line below?

Mathematics

1 answer:

murzikaleks [220]3 years ago

4 0

Answer:

The number line is missing, but as we are know that the number marked in the number line is -6/4, i will guess that the ticks are spearated by fourts (the distance between each tick is 1/4).

Now, for the number at the right of -6/4, we should add the distance for one tick, this means that the number at the right is:

-6/4 + 1/4 = -5/4.

Now i will give some other examples:

Now, if the distance between ticks is 2/4, then the number at the right will be:

-6/4 + 2/4 = -4/4 = -1

Now, if the distance between ticks is 3/4, the the number at the right will be:

-6/4 + 3/4 = -3/4.

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zalisa [80]

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3 years ago

The number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.05

Tresset [83]

Answer:

(a) Probability that there are no surface flaws in an auto's interior is 0.6065 .

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws is 0.00673 .

Step-by-step explanation:

We are given that the number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.05 flaws per square foot of plastic panel.

Let X = Distribution of number of surface flaws in plastic panels

So, X ~ Poisson( $\lambda$ )

The mean of Poisson distribution is given by, E(X) = $\lambda$ = 0.05

which means, X ~ Poisson(0.05)

The probability distribution function of a Poisson random variable is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!}; for x=0,1,2,3...$

Now, we know that $\lambda$ for per square foot of plastic panel is 0.05 and we are given that an automobile interior contains 10 square feet of plastic panel.

Therefore, for 10 square foot of plastic panel is = 10 * 0.05 = 0.5

(a) Probability that there are no surface flaws in an auto's interior =P(X=0)

P(X = 0) = $\frac{e^{-0.5}*0.5^{0}}{0!}$ = $e^{-0.5}$ = 0.6065

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws = $P(X = 0)^{10}$

So, $P(X = 0)^{10}$ = $0.6065^{10}$ = 0.00673

8 0

3 years ago

Can someone please help me please?

Mekhanik [1.2K]

$\large \mathfrak{Answer : }$

The equation of the red parabola is :

$f(x) = 1 - {x}^{2}$

therefore , correct option in A

8 0

3 years ago

????????????????????

Snowcat [4.5K]

Greetings!

Substitute:
$x+y=1000 \\ x=1000-y$
Now we can input this into the other equation so, we only have one variable.

Solve for y.
$0.05(1000-y)+0.06y=57$
Distribute the parenthesis.
$50-0.05y+0.06y=57$
Combine Like Terms.
$50-0.01y=57$
Add -50 to both sides.
$(50-0.01y)+(-50)=(57)+(-50)$
Simplify.
$0.01y=7$
Divide both sides by 0.01.
$(0.01y)/0.01=(7)/0.01$
Simplify.
$y=700$

Input this value into the other equation.
$x+700=1000$
Add -700 to both sides.
$(x+700)+(-700)=(1000)+(-700)$
Simplify.
$x=300$

The answer would be 300,700

Hope this helps.
-Benjamin

8 0

3 years ago

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aalyn [17]

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2 years ago