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Afina-wow [57]
3 years ago
10

-6x + 14 < -28 AND 3x + 28 < 25

Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0

Answer:

x>7

-6x+14< -28

-14. -14

-6x<-42

÷-6 ÷-6

x<7

switch signs because we divided by a negative number

x>7

Answer: x<-1

3x+28<25

-28 -28

3x<-3

÷3 ÷3

x<-1

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Bezzdna [24]

26 divided by 10.92 equals 2.380952

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The perimeter of a rectangular field is 200 feet. The length of the field is 7 feet more than two times the width of the field.
bulgar [2K]
X = 2y + 7 ...............(1)
2x + 2y = 200 ........(2)

Substituting the expression for x in equation (1) into equation (2) gives
2(2y + 7) + 2y = 200 .....(3)
Equation (3) simplifies to
6y = 186
Therefore y = 31 feet.
Substituting the value for y into (1) gives
x = 69 feet.
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Write 5 5/9 as a improper fraction
4vir4ik [10]
5 5/9
5 * 5/9
25/9
The correct answer is 25/9, as shown above.
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What is the value of 2(8-5) to the second power?
postnew [5]
The answer would be 18.
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2 years ago
Complete the point-slope equation of the line through (1,3) (5,1) y-3=?
MaRussiya [10]

Answer:

\huge\boxed{y-3=-\frac{1}{2}(x-1)}

Step-by-step explanation:

Point-slope is:

y-y_1=m(x-x_1)

m-\text{This represents the slope.}\\\\(x_1,y_1)-\text{This represents the point used in the equation.}

<h2>Our goal: </h2>

We have to complete the point-slope equation of the line through (1,3) (5,1).

--------------------------------------------------------

We have a incomplete equation of the line.

y-3=m(x-x_1)

We need to find the <u>slope</u> of the line, and the <u>value</u> of  x_1.

--------------------------------------------------------

<h3>Finding 'x1':</h3>

It seems that the value of 3 was used to be y_1. This means that the point (1,3) was used for the equation. This means that x_1 would have to be 1.

<h3>Finding Slope:</h3>

Slope is rise over run.

m=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1}

We are given the points (1,3) and (5,1).

m=\frac{1-3}{5-1}=\frac{-2}{4}=\frac{-1}{2}=\boxed{-\frac{1}{2}}

The slope is one-half.

--------------------------------------------------------

We now have enough information to complete the point-slope equation.

{\left \{ {{x_1=1} \atop {m=-\frac{1}{2} }} \right.}\\\\y-3=m(x-x_1)\rightarrow\boxed{y-3=-\frac{1}{2}(x-1)}

Our final equation is:

y-3=-\frac{1}{2}(x-1)

6 0
3 years ago
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