Answer:
6km
Step-by-step explanation:
Area of circle = πr²
Where r = radius, π= 3.14, A = 28.26km²
A = 3.14 x r²
3.14 r2 = 28.26
Divide both sides by 3.14
r²= 28.26/3.14
r² = 9
Square root both sides
r= √9
r= 3
Radius = 3km
Note : Diameter = 2 x radius
Diameter = 3 x 2
Diameter = 6km
I hope this was helpful, Please mark as brainliest.
Answer: 18
Step-by-step explanation:
The least common denominator of
and
is going to be a multiple of 9 and 6. Let us list them out:
9: 9, <u>18</u>, 27, 36, 45, 54, 63, 72, 81, 90
6: 6, 12, <u>18</u>, 24, 30, 36, 42, 28, 54, 60
You can see I bolded and underlined 18. Why? This is the first common multiple of 9 and 6 so it is our least common denominator (LCD).
Remark
I'm not sure I know what you mean, but I will answer trying to interpret it so it fits the description of the question.
Step One: Set up the equation. The normal way of solving this would be to use the Cos function.
Cos(theta) = Adjacent / hypotenuse = x/8 Multiply both sides by 8
8*cos(theta) = x Theta = 35
8*cos(35) = x This is about as simple a way as is possible.
6.553 = the height of the sale.
Step Three: try using the reciprocal
1 / cos(35)= hypotenuse / adjacent
1/0.8191 = 8/x cross multiply
x = 0.8191 * 8
x = 6.553
Answer:
Step-by-step explanation:
Hello!
The objective is to test if people with less social contact get more colds than people who are involved in a variety of social activities.
For this, a sample of 276 healthy men and women was taken.
n₁= 96 had few social outlets
n₂= 105 had six or more activities
These two groups were exposed to the cold virus and the following proportions of individuals that got sick were obtained:
p'₁= 0.62 (62% of the people with few social outlets got sick)
p'₂= 0.35 (35% of the people with six or more activities got sick)
The study variables are X₁: number of people with few social outlets that got sick after being exposed to the cold virus, in a sample of 96, and X₂: number of people with six or more activities that got sick after being exposed to the cold virus, in a sample of 105.
You have to construct a 99% CI for the difference these two populations since there is no specific order given I'll estimate: p₁ - p₂
(p'₁ - p'₂) ± 

(0.62-0.35) ± 2.586 
[0.094; 0.045]
With a 99% confidence level, you'd expect that the difference between the proportion of people with few social outlets that got sick and the proportion of people with six or more social activities that got sick after being exposed to the cold virus.
I hope it helps!