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makkiz [27]
3 years ago
5

What is the answer to 4/5+9/11

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
7 0
Hi there! 
When adding fractions we ALWAYS need to make sure the that denominators are the SAME .We need to find a common denominator so that the two fractions are on the same terms. In the end, the denominator stays the same. Let's start: 
We are given 2 fractions to add: 
\frac{4}{5} + \frac{9}{11}

We need to find a LEAST common denominator, start by listing the factors of 5 and 11 since both of these numbers are in the denominator. 

Factors of 5: <span>5, 10, 15, 20, 25, 30, 35, 40, 45, 50, </span><span>55
Factors of 11: </span><span>11, 22, 33, 44, </span><span><span>55

</span>As we see above, 55 is our LCD (least common denominator) 

We can change the denominator of both fractions to 55 since this is our LCD:
</span>\frac{4}{55} + \frac{9}{55}

However, if the denominator changes, the numerator changes as well. We use the following formula to find the numerators: 

(Common Denominator ÷ Denominator) x Numerator =  Numerator

Lets start by finding the numerator for the first fraction: 
4/55

<span>(55 (common denominator) ÷ 5 (original denominator) × 4 (numerator) = 44</span>

The first fraction becomes: 

\frac{44}{55}

Now let's do the second:

9/55

<span>(55(common denominator) ÷ 11(original denominator))×9(</span>numerator) = 45

Now we have: 

\frac{45}{55}

Now we have two fractions to add: 

\frac{44}{55} + \frac{45}{55}

Only add the numerators, the denominators stay the SAME !

44+45=89

Final answer: \frac{89}{55}

If you have further questions on this problem, please do not hesitate to comment below! :) Have a nice day! 

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The angles of two pentagons are all equal to 108°. The length of one side of each pentagon measures 11 cm.
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There is not enough information to determine whether the pentagons are congruent.

3 0
3 years ago
What is the nth term of the sequence -2 -8 -18 -32 -50
andreev551 [17]

Answer:

-2n²

Step-by-step explanation:

Using the image attached:
We see that the second differences (blue ones) are all equal so we conclude that this is a quadratic sequence.
The quadratic sequence has the form:
T_{n} = an^{2}  +bn +c

To find the value of a we just divide second difference ( -4 ) by 2:

  • a = \frac{-4}{2}= -2

Now we have:

  • T_{n}= -2n^{2}  +bn+c

Substitute n_{1} and n_{2} into the equation above:

  • T_{1} = -2(1)^{2}  +b(1) +c
  • T_{2} = -2(2)^{2}  +b(2)+c

Since T_{1} = -2 and T_{2} = -8 , after simplification we have:

  • b +c =0
  • 2b+c=0

The solution of this system is:

  • b=0, c =0

The general term is :

T_{n} = -2n^{2}

6 0
2 years ago
If a cat with short brown hair (llBb) is crossed with a cat with long black hair (Llbb), what is the likelihood that there will
Advocard [28]

Bb = brown hair phenotype

bb = black hair phenotype

we see that B = brown hair is the dominant gene while b = black hair is the recessive gene

----------------------------------

ll = short hair, this is a lowercase L

Ll = long hair

In this case, l = short hair is the recessive gene while L = long hair is the dominant gene.

----------------------------------

Check out the diagram below to see the dihybrid crosses for each of the hair color and hair length genotypes. From there, I show all of the genotypes possible for any offspring. Those genotypes are

  • LlBb  = long brown hair (comes up 4 times)
  • Llbb  = long black hair (comes up 4 times)
  • llBb  = short brown hair (comes up 4 times)
  • llbb  = short black hair (comes up 4 times)

-----------------------------------

If we are talking about 1 offspring, then it is not possible for him/her to have both "long black hair AND short brown hair" as the instructions state. So let's consider two offspring instead.

The probability of having long black hair is 4/16 = 1/4 as there are 4 cases of Llbb out of 16 cases total. Similarly, the probability of getting llBb is 4/16 = 1/4 as well, for pretty much the same reasons.

The probability of having both events occur is (1/4)*(1/4) = 1/16

The multiplication of probabilities is valid because the two events are independent.

==============================================

<h3>Final Answer: A) 1/16</h3>

5 0
3 years ago
Simplify the given expression below: 4 divided by the quantity of 3 minus 2i
svetoff [14.1K]
This is rationalising the denominator of an imaginary fraction. We want to remove all i's from the denominator.

To do this, we multiply the fraction by 1. However 1 can be expressed in an infinite number of ways. For example, 1 = 2/2 = 3/3 = 4n^2 / 4n^2 (assuming n is not zero!). Let's express 1 as the complex conjugate of the denominator, divided by the complex conjugate of the denominator.

The complex conjugate of (3 - 2i) is (3 + 2i). Then do what I just said:

4/(3-2i) * (3+2i)/(3+2i) = 4(3+2i)/(3-2i)(3+2i) = (12+8i)/(9-4i^2) = (12+8i)/(9+4) = (12+8i)/13

This is the answer you are looking for. I hope this helps :)
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