Pllzz help me I am timed!
1 answer:
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The figure of the prism is attached below.
The total surface area of the prism equals the sum of areas of two triangles and the three rectangles.
Surface Area of Prism = Area of 2 Triangles + Area of 3 Rectangles.
Area of a Triangle = 0.5 x Base x Height
Area of a Triangle = 0.5 x 3 x 4 = 6 square units
There are 3 rectangles. From the figure we can see that the bottom most rectangle has the dimensions 4 by 6. The left most rectangle has the dimensions 3 x 6 and the right most rectangle has the dimensions 5 by 6.
So, the Area of 3 rectangles will be = (4 x 6) + (3 x 6) + (5 x 6) = 72 square units
The Surface Area of the prism will be:
Surface Area = 2 (4) + 72 = 84 square units
Thus the correct answer is option A
The total surface area of the prism equals the sum of areas of two triangles and the three rectangles.
Surface Area of Prism = Area of 2 Triangles + Area of 3 Rectangles.
Area of a Triangle = 0.5 x Base x Height
Area of a Triangle = 0.5 x 3 x 4 = 6 square units
There are 3 rectangles. From the figure we can see that the bottom most rectangle has the dimensions 4 by 6. The left most rectangle has the dimensions 3 x 6 and the right most rectangle has the dimensions 5 by 6.
So, the Area of 3 rectangles will be = (4 x 6) + (3 x 6) + (5 x 6) = 72 square units
The Surface Area of the prism will be:
Surface Area = 2 (4) + 72 = 84 square units
Thus the correct answer is option A
Answer:
a.
Step-by-step explanation:
We are asked to find the probability of getting 3 heads on 4 flips.
Since we know that flipping a fair coin has 2 equally likely possible outcomes, so flipping four coins will have possible outcomes.
Sample space of possible outcomes.
HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT,
THHH, THHT, THTH,THTT, TTHH, TTHT, TTTH, TTTT.
We can see that there are 4 favorable outcomes of getting heads.
Therefore, the probability of getting 3 heads on 4 coins will be and option a is the correct choice.