What are four consecutive integers whose sum is 682

2 answers:

7 0

X, x+1, x+2, x+3 - four consecutive integers

$x+x+1+x+2+x+3=682 \\
4x+6=682 \ \ \ |-6 \\
4x=676 \ \ \ |\div 4 \\
x=169 \\ \\
x+1=169+1=170 \\
x+2=169+2=171 \\
x+3=169+3=172$

The integers are 169, 170, 171 and 172.

egoroff_w [7]3 years ago

3 0

X+(x+1)+(x+2)+(x+3)=682.
4x+1+2+3=682
4x+6=682
4x=676
X=169

So it's 169, 170, 171, 172

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