That would be the median I think...
Answer:
is the equation of this parabola.
Step-by-step explanation:
Let us consider the equation


![\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}](https://tex.z-dn.net/?f=%5Cmathrm%7BRange%5C%3Aof%5C%3A%7D-4x%5E2%3A%5Cquad%20%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Af%5Cleft%28x%5Cright%29%5Cle%20%5C%3A0%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A0%5D%5Cend%7Bbmatrix%7D)

As











Therefore, the parabola vertex is





so,

Therefore,
is the equation of this parabola. The graph is also attached.
To factor both numerator and denominator in this rational expression we are going to substitute

with

; so

and

. This way we can rewrite the expression as follows:

Now we have two much easier to factor expressions of the form

. For the numerator we need to find two numbers whose product is

(30) and its sum

(-11); those numbers are -5 and -6.

and

.
Similarly, for the denominator those numbers are -2 and -5.

and

. Now we can factor both numerator and denominator:

Notice that we have

in both numerator and denominator, so we can cancel those out:

But remember than

, so lets replace that to get back to our original variable:

Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is


Answer:
12.045 is already in base 10, since it can'be binary or hexadecimal,
it's a denary(decimal) number, and decimal numbers are base 10