Answer:
315 chocolate
Step-by-step explanation:
Let Sam's chocolate be S
Let Clariss's chocolate be C
When Sam gave Clarissa 105 chocolates, Clarissa had 5 times as many chocolates as Sam.
This can be written as:
C = 5S
The sum of their chocolate is 504 i.e
S + C = 504
Now, let us determine the chocolate of Clarissa after receiving 105 chocolate from Sam. This can be obtained as follow:
S + C = 504
But: C = 5S
S + 5S = 504
6S = 504
Divide both side by 6
S = 504/6
S = 84.
C = 5S = 5 x 84 = 420
Therefore, Clarissa have 420 chocolate after receiving 105 chocolate from Sam.
Now, to know the amount of chocolate that Clarissa has at first, we simply subtract 105 from the present amount that Clarissa have. This is illustrated below:
Amount of chocolate that Clarissa has a first = 420 – 105 = 315
Therefore, Clarissa had 315 chocolate at first.
Answer:
-14
Step-by-step explanation:
Range is the difference between the lowest and highest values.
Answer:
31,250
Step-by-step explanation:
32,000,000x0.5= 16,000,000
repeat the process 10 times and you've got 31,250
Answer: 48 tickets
Step-by-step explanation:
Since the expression that gives the number of tickets a player wins if he shoots the ball in the hoop t times is expressed as 3t.
Therefore, the number of tickets that a player wins if he shoots the ball in the hoop 16 times will be:
= 3t
where,
t = 16
Therefore, 3t = 3 × 16 = 48
The player wins 48 tickets.
Answer:
(x, y) = (- 13/2 + 3/2 * y, y) ,y in mathbb R
Step-by-step explanation:
4x-6y=-26
-2x+3y-13
4x-6y=-26
x=-13/2+3/2y
4(-13/2+3/2y) - 6y=-26
y in mathbb R
x, y) = (- 13/2 + 3/2 * y, y) ,y in mathbb
