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3 years ago

Factor n 3 - n 2 + 3n - 3.

Mathematics

2 answers:

sp2606 [1]3 years ago

8 0

(n^2+ 3)(n - 1)
Hope this helps add me ♥

Ronch [10]3 years ago

4 0

(n^2+ 3)(n - 1)
I think

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MrMuchimi

Answer:

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Step-by-step explanation:

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3 years ago

Write an equation for a line that is parallel to 3y = 2x - 3 and passes through the point (-3, 4).

liraira [26]

Answer:

Step-by-step explanation:

You keep the same slope since it's supposed to be parallel. But first you need to write it in slope intercept form. So the y can't have a number in front of it, so you must divided everything after the equal sign by the 3. So the equation becomes y=2/3x−1. Now you plug in the points to find a parallel equation using point slope form y−(4)=(23)(x−(−3)). Then you solve that and you get y=2/3x+6.

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3 years ago

Is 170 going to be even or odd

kicyunya [14]

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3 0

3 years ago

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Find the sum of the numbers if their sum is -11 and their difference is 41

Lostsunrise [7]

Answer:

-52

Step-by-step explanation:

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3 years ago

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7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

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