The answer is 18...................................,...............

lesantik [10]

Answer:

8. ∠1=118° ∠2=118°

9. ∠1=72° ∠2=108°

10. ∠1=127° ∠2=127°

Step-by-step explanation:

8. In this problem, 118° is corresponding to ∠1, meaning they are congruent. ∠2 is supplementary with ∠1, meaning that together, they equal 180°. So, to get ∠2, you must subtract 118° from 180°

9. In this problem, 72° is same side interior with ∠1, meaning they are congruent. ∠2 is supplementary with ∠1, so you do 180°-72°= 108°

10. In this problem, ∠1 is vertical angles with 127°, making them equal to each other. ∠2 is corresponding with 127°, making them also equal.

5 0

2 years ago

What are the answers for 7 and 8??? please help

wolverine [178]

Answer:

7.)

Therefore FT is 33 unit.

8.)

Therefore SU is 98 unit.

Step-by-step explanation:

7.)

Given:

ΔFUT ~ ΔFHG

FU = 39

FH = 130

FG = 110

To Find:

FT = ?

Solution:

ΔFUT ~ ΔFHG ............Given

If two triangles are similar then their sides are in proportion.

$\dfrac{FU}{FH} =\dfrac{FT}{FG} \textrm{corresponding sides of similar triangles are in proportion}\\$

Substituting the values we get

$\dfrac{39}{130} =\dfrac{FT}{110}\\\\FT=\dfrac{110\times 39}{130}=33\\FT=33\ unit$

Therefore FT is 33 unit.

8.)

Given:

ΔSTU ~ ΔFED

ST= 63

FE = 9

FD = 14

To Find:

SU = ?

Solution:

ΔSTU ~ ΔFED ............Given

If two triangles are similar then their sides are in proportion.

$\dfrac{ST}{FE} =\dfrac{SU}{FD} \textrm{corresponding sides of similar triangles are in proportion}\\$

Substituting the values we get

$\dfrac{63}{9} =\dfrac{SU}{14}\\\\SU=\dfrac{882}{9}=98\\\\SU=98\ unit$

Therefore SU is 98 unit.

5 0

3 years ago

If you can answer this question you'll get brainliest.

igomit [66]

Answer:

Volume = 66 cm³

Step-by-step explanation:

Area of the oblique triangular prism = Area of the triangular base × Vertical height from the base

From the figure attached,

Area of the triangular base = $\frac{1}{2}(\text{Base})(\text{Height of the right triangle})$

= $\frac{1}{2}(3)(4)$

= 6 cm²

Vertical height of the given oblique prism = 11 cm

Volume of the given oblique prism = 6 × 11

= 66 cm³

4 0

3 years ago

Read 2 more answers

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$