All categories

3 years ago

The answer is 18...................................,...............

Mathematics

1 answer:

vesna_86 [32]3 years ago

3 0

the equation is 6x3...............................................................

You might be interested in

I need help woth question and my test

Maksim231197 [3]

Answer:

28.26 $cm^2$

Step-by-step explanation:

The area of the quarter circle is the area of the circle / 4. Thus, the area is $\frac{\pi r^2}{4}$ = $\frac{3.14*6^2}{4}$ = 28.26 square centimeters

8 0

3 years ago

Read 2 more answers

Please answer this (question on image enclosed)

Anit [1.1K]

Answer:

its 900

Step-by-step explanation:

5 0

3 years ago

If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn

mash [69]

Let $a=\tan A$ and $b=\sin A$ . Then

$m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab$

$\implies m^2-n^2=4\tan A\sin A$

and

$mn=(a+b)(a-b)=a^2-b^2$

$\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}$

The expression under the square root can be rewritten as

$\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)$

Recall that

$\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A$

so that

$\tan^2A-\sin^2A=\sin^2A\tan^2A$

and assuming $\sin A>0$ and $\tan A>0$ , we end up with

$4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A$

so that

$m^2-n^2=4\sqrt{mn}$

as required.

5 0

3 years ago

Solve the quadratic equation (x-3)2 = 49

Tresset [83]

27.5, because 27.5-3=24.5 and 24.5x2= 49

3 0

3 years ago

What is the difference? <br><br>( -4x + 3) - (7x -<img src="https://tex.z-dn.net/?f=3x%5E%7B2%7D" id="TexFormula1" title="3x^{2}

trapecia [35]

The answer is 3x^2-19x+1

(-4x+3)-(7x-3x^2-1)
-12x+7x+3x^2+1

Combine like terms:
3x^2+(-12x+-7x)+1
= 3x^2+-19x+1

3 0

3 years ago