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3 years ago

If a = band b = c, which statement must be true?

Mathematics

1 answer:

sammy [17]3 years ago

7 0

Answer:

if a = b and b= c then a,b and c are all equal

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the ratio of the length of a rectangle to its width is 8 to 5. if the longer side of the rectangle is 20 ft, what is the length

expeople1 [14]

8/5 = 20/x
8x = 20(5)
8x = 100
x = 12.5

answer
<span>length of its shorter side = 12.5 ft</span>

8 0

3 years ago

Read 2 more answers

What is the half of 14.5

Aleks04 [339]

Answer:

7.25

Explanation:

14.5×½=7.25

3 0

3 years ago

Read 2 more answers

Two planes that are traveling toward each other are 720 miles apart. One plane is traveling 40 miles per hour faster than the ot

natali 33 [55]

Answer:

y = 460 miles per hr

x = 500 miles per hr

Step-by-step explanation:

Let the planes be X any

Let their speeds be xmiles/hr and ymiles/hr respectively

x = y + 40 (assuming X is faster by 40miles/hr)

Distance travelled by X to meet Y = 0.75x

Distance travelled by Y to meet X = 0.75y

0.75x + 0.75y = 720 --------1

Put x = y + 40 in eqn 1

0.75(y+40) + 0.75y = 720

0.75y + 30 + 0.75y= 720

1.5y = 690

y = 460 miles per hr

x = 460 +40

= 500 miles per hr

7 0

2 years ago

Please Help Me!<br> *Question Is Below Here*

SCORPION-xisa [38]

The product of this equation is 21 when the values of X and Y are imputed into the equation.

5 0

3 years ago

Read 2 more answers

I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ

kumpel [21]

Answer:

side of 6.124 ft and height of 3.674 ft

Step-by-step explanation:

Let's s be the side of the square base and h be the height of the rectangular box.

The base and the roof would have an area of $s^2$ and cost of

$4s^2 + 2s^2 = 6s^2$

The sides would have an area of 4sh and cost of 4sh*2.5 = 10sh

So the total cost for the material is

$6s^2 + 10sh = 450$

$10sh = 450 - 6s^2$

$h = 45/s - 0.6s$

The volume of the shed has the following formula

$V = s^2h = s^2(45/s - 0.6s) = 45s - 0.6s^3$

To find the maximum value for V, we can take its first derivative, and set it to 0

$\frac{dV}{ds} = 45 - 1.2s^2 = 0$

$1.2s^2 = 45$

$s^2 = 45 / 1.2 = 37.5$

$s = \sqrt{37.5} = 6.124 ft$

h = 45/s - 0.6s = 3.674 ft

4 0

3 years ago