5(5+x) = 6(6+4)
25+5x = 60
5x = 35
x = 7
-----------------
3(3+5) = 4(4+x)
24 = 16 + 4x
4x = 24-16
4x = 8
x = 2
Answer:
55
Step-by-step explanation:
Let x represent the middle integer. Then the smallest is x-2 and the largest is x+2. Your requirement is that ...
(x-2)/(x+2) > 2/3
3x -6 > 2x +4 . . . . cross multiply
x > 10 . . . . . . . . . . .add 6-2x
The smallest integer satisfying this requirement is x=11. The sum of the 5 integers is 5x = 55.
The smallest sum is 55.
X would be -5
Hope this helps :)
For this equation you would use Pythagorean's theorem. Which is super helpful in finding missing sides of triangle. so a^2 + b^2 = c^2. The only tricky part is having to remember that C IS ALWAYS THE LONG SIDE OF THE TRIANGLE. Always and forever! The equation you would use to figure this out would be:
29^2 + b^2 = 51^2
And the solve for b.
I hope this helped! :)
