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Vesnalui [34]
3 years ago
14

HHHEEELLPPP PPPLLLEEASEEE!!!!!! PLZZ HELP ME I GIVE BRAINLIEST!!!!!!!PZL HELP ME

Mathematics
1 answer:
ozzi3 years ago
5 0
Okay, we can use the functions in parts 3 and 4 since we want to calculate how many points will be deducted for 3 falls and how many points are earned for 4 seconds on the rail trick.

Part 3 function:
\sf y=1.6x

He fell 3 times, so plug this in for 'x':

\sf y=1.6(3)

Multiply:

\sf y=4.8

So he will receive a 4.8 point deduction for falling 3 times.

Part 4 function:
\sf y=7x+10

Where 'x' is the seconds he does the trick. He did it for 4 seconds, so let's plug that in for 'x':

\sf y=7(4)+10

Multiply:

\sf y=28+10

Add:

\sf y=38

So he will receive 38 points for the 4-second rail trick.
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Find the quartic function that is the best fit for the data in the following table.
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Answer:

hdhdhd

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7 0
2 years ago
On a school trip, the ratio of the teachers to students is 2:21. The ratio boys to girls is 4:3. If there are 18 girls girls on
Alexandra [31]

Answer:

4

Step-by-step explanation:

Let's say B is the number of boys and T is the number of teachers.

T / (B + 18) = 2/21

B/18 = 4/3

Solve the second equation for B.

B = 24

Plug into the first equation to find T.

T / (24 + 18) = 2/21

T = 4

6 0
3 years ago
What is the image point of (-6,3) after a translation right 5 units and down 3 units?
kobusy [5.1K]
Answer:
(-1,0)
step-by-step explanation:
(-6,3)
right 5
(-1,3)
down 3
(-1,0)
6 0
3 years ago
solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
Hi ! please help !
tatuchka [14]

Hey there! I was looking at your question for a bit then realized you meant i, the imaginary number, not "1" at the end of each number.

  • Complex numbers are numbers involving both real and imaginary numbers; thus, this question wouldn't make much sense without the imaginary number i

The expression we are given is:

(3+4i)+(8+2i)

Open parenthesis and combine like terms:

=3+4i+8+2i

=11+6i

This is answer choice B (assuming it's supposed to be an i and not a "1" at the end)

Let me know if you need any clarifications, thanks!

~ Padoru

5 0
3 years ago
Read 2 more answers
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