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scoray [572]
4 years ago
15

Hal’s Sporting goods had a 1 day sale. The original price of a mountain bike was 325. On salthe it was 276.25. What is the perce

nt decrease for this sale?
Mathematics
1 answer:
cricket20 [7]4 years ago
8 0
To find this, first do 276.25/325 to get .85. Next subtract .85 from 1 to get .15 which is the decimal version of how much it was off. Multiply by 100 to get percent. 15% if the percent decrease for this sale.
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I tried and found that it is 2 am i correct? if not what is the correct answer and how do u know please :)
Mumz [18]
Nope, the answer is three. Mean means the average of all the numbers. So all you have to do is to add the numbers up and divide the the amount of numbers with your sum.
6 0
3 years ago
1 over 8 added 5 times equals​
leonid [27]

Answer:

5/8 or 41/8

Step-by-step explanation:

If you mean 1/8 x 5, then that equals 5/8

If mean 1/8 + 5, then that equals 41/8

3 0
3 years ago
Sophie earns $7 an hour babysitting and $8 an hour for cleaning the house last week she babysat for 3 hours and clean for 2 hour
Trava [24]

Answer: I think the answer is 37

4 0
3 years ago
(1 point) The matrix A=⎡⎣⎢−4−4−40−8−4084⎤⎦⎥A=[−400−4−88−4−44] has two real eigenvalues, one of multiplicity 11 and one of multip
serious [3.7K]

Answer:

We have the matrix A=\left[\begin{array}{ccc}-4&-4&-4\\0&-8&-4\\0&8&4\end{array}\right]

To find the eigenvalues of A we need find the zeros of the polynomial characteristic p(\lambda)=det(A-\lambda I_3)

Then

p(\lambda)=det(\left[\begin{array}{ccc}-4-\lambda&-4&-4\\0&-8-\lambda&-4\\0&8&4-\lambda\end{array}\right] )\\=(-4-\lambda)det(\left[\begin{array}{cc}-8-\lambda&-4\\8&4-\lambda\end{array}\right] )\\=(-4-\lambda)((-8-\lambda)(4-\lambda)+32)\\=-\lambda^3-8\lambda^2-16\lambda

Now, we fin the zeros of p(\lambda).

p(\lambda)=-\lambda^3-8\lambda^2-16\lambda=0\\\lambda(-\lambda^2-8\lambda-16)=0\\\lambda_{1}=0\; o \; \lambda_{2,3}=\frac{8\pm\sqrt{8^2-4(-1)(-16)}}{-2}=\frac{8}{-2}=-4

Then, the eigenvalues of A are \lambda_{1}=0 of multiplicity 1 and \lambda{2}=-4 of multiplicity 2.

Let's find the eigenspaces of A. For \lambda_{1}=0: E_0 = Null(A- 0I_3)=Null(A).Then, we use row operations to find the echelon form of the matrix

A=\left[\begin{array}{ccc}-4&-4&-4\\0&-8&-4\\0&8&4\end{array}\right]\rightarrow\left[\begin{array}{ccc}-4&-4&-4\\0&-8&-4\\0&0&0\end{array}\right]

We use backward substitution and we obtain

1.

-8y-4z=0\\y=\frac{-1}{2}z

2.

-4x-4y-4z=0\\-4x-4(\frac{-1}{2}z)-4z=0\\x=\frac{-1}{2}z

Therefore,

E_0=\{(x,y,z): (x,y,z)=(-\frac{1}{2}t,-\frac{1}{2}t,t)\}=gen((-\frac{1}{2},-\frac{1}{2},1))

For \lambda_{2}=-4: E_{-4} = Null(A- (-4)I_3)=Null(A+4I_3).Then, we use row operations to find the echelon form of the matrix

A+4I_3=\left[\begin{array}{ccc}0&-4&-4\\0&-4&-4\\0&8&8\end{array}\right] \rightarrow\left[\begin{array}{ccc}0&-4&-4\\0&0&0\\0&0&0\end{array}\right]

We use backward substitution and we obtain

1.

-4y-4z=0\\y=-z

Then,

E_{-4}=\{(x,y,z): (x,y,z)=(x,z,z)\}=gen((1,0,0),(0,1,1))

8 0
3 years ago
A 943-foot tree has grown at a constant rate each year. In the equation below, t is the age of the three in years.
Mazyrski [523]

Answer:

B. 41 feet per year

Step-by-step explanation:

943/23= 41

Total feet / coefficient= feet per year

7 0
3 years ago
Read 2 more answers
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