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Ivahew [28]
3 years ago
5

Gus has a fish tank that holds 4710 inches cubed of water. He is using a cylinder shaped bucket with a radius of 5 inches and a

height of 20 inches to fill the tank. How many times will Gus need to fill the bucket to completely fill the fish tank if he doesn't spill a drop
Mathematics
2 answers:
KatRina [158]3 years ago
4 0
For a cylinder, V=pi x r^2 x h
So the volume of the cylinder is about v = 3.14(5^2)20 = 1570 cubic inches.
Divide 4710 by that number and the answer I’d that Gus has to fill the bucket 3 times
aksik [14]3 years ago
3 0
<h2>Answer:</h2>

Hence, the number of times will Gus need to fill the bucket to completely fill the fish tank if he doesn't spill a drop is:

                        3 times

<h2>Step-by-step explanation:</h2>

The amount of water that a tank can hold is: 4710 inches cube.

This means that the volume of tank is: 4710 cubic inches.

Also, the bucket is in the shape of a cylinder with radius 5 inches and height 20 inches.

This means that the Volume of bucket is given by:

Volume=\pi r^2h

where r denotes radius and h denotes height.

Hence, Volume of bucket is:

Volume=\pi\times (5)^2\times 20\\\\\\Volume=3.14\times 25\times 20\\\\\\Volume=1570\ cubic\ inches

Let n be the number of times Gus need to fill the bucket to completely fill the fish tank

Hence, we have:

 Volume of fish tank= n × Volume of Bucket

i.e.  4710=n\times 1570\\\\i.e.\\\\n=\dfrac{4710}{1570}\\\\n=3

               Hence, the answer is:

                          3

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138.43-19.99=118.44
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6 0
3 years ago
The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0
3 years ago
What's the angle of y and x ??
victus00 [196]
Y is going to be the number 40
x will equal 90
6 0
3 years ago
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
2 years ago
The scores awarded to 25 students for an assignment were as follows
Kisachek [45]

Answer:

<h2>Here</h2>

The numbers less than 50 (A) = 4

Total numbers (S) = 14

Probability students below 50 = 4÷14

Step-by-step explanation:

That is the correct answer of it.

3 0
2 years ago
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