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2 years ago

I do need help with this problem that includes pi. ^_^

Mathematics

1 answer:

Troyanec [42]2 years ago

5 0

Solution:

Note that:

Circumference = 50.24 ft = 2πr = πd
Dia. = 16 ft.

Divide the diameter both sides.

50.24 ft = πd
=> 50.24/d ft = πd/d
=> 50.24/d ft = π

Substitute the diameter in the equation.

=> 50.24/16 = π (Option A)

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A carpenter has 16 1/2 m of wood. He cuts the wood into pieces that are each 2 3/4 m long.

mario62 [17]

So your question is how pieces are there?? If it is:
Its 2 pieces plus a 0.36m leftover

6 0

3 years ago

Using the side lengths

In-s [12.5K]

Given

The three sides are given 24, 30 and 18.

Explanation

To find the triangle is acute, obtuse or right triangle.

To determine whether the triangle is acute, right, or obtuse.add the squares of the two smaller sides, and compare the sum to the square of the largest side. Since this sum is greater, the triangle is acute.

If the sum of the squares of the two smaller sides is equal to the square of the largest side , then it is right triangle.

Now c.

$\begin{gathered} 30^2=24^2+18^2 \\ 900=576+324 \\ 900=900 \end{gathered}$

Answer

Hence the sum of the squares of the two smaller sides is equal to the square of the largest side , then it is right triangle.

The correct option is A.

3 0

1 year ago

If 1 inch is about 2.54 cm, how many inches are in 16 cm?

ozzi

6.299 or 6.3 depending on how it wants you to round

16cm / 2.54 cm per in = 6.3 inches

8 0

3 years ago

Trevon and Riggs are brothers.

lord [1]

Answer:

Trevon is 28 years old

Step-by-step explanation:

Riggs =x

Trevon =7+x

7+x+x=49

7+2x=49

2x=49-7

2x=42

x=21

Trevon is 21+7= 28 years old

3 0

3 years ago

Read 2 more answers

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago