Step-by-step explanation:
f(x) = x² + x + 3/4
in general, such a quadratic function is defined as
f(x) = a×x² + b×x + c
the solution for finding the values of x where a quadratic function value is 0 (there are as many solutions as the highest exponent of x, so 2 here in our case)
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = 1
c = 3/4
x = (-1 ± sqrt(1² - 4×1×3/4))/(2×1) =
= (-1 ± sqrt(1 - 3))/2 = (-1 ± sqrt(-2))/2 =
= (-1 ± sqrt(2)i)/2
x1 = (-1 + sqrt(2)i) / 2
x2 = (-1 - sqrt(2)i) / 2
remember, i = sqrt(-1)
f(x) has no 0 results for x = real numbers.
for the solution we need to use imaginary numbers.
Answer:
2a + 30
Step-by-step explanation:
break it down so it is 4(a+5)
then work out -2(a-5)
so 4 x a then 4 x 5 which gives 4a + 20
then -2 x a then -2 x -5 which gives -2a + 10
then when you have 4a + 20 -2a + 10
do 4a - 2a which is 2a
do 20 + 10 which is 30
so the answer comes to 2a + 30
if anything doesnt seem right just comment and i will correct
hope this helps :)
