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zavuch27 [327]
3 years ago
7

Elizabeth is a manager at a nursery and is in charge of displaying potted trees in rows. Elizabeth has 330 citrus trees and 180

palm trees. She wants to make rows of trees so that each row has the same number of trees and each tree is in a row. If the citrus trees and the palm trees must not be mixed in the​ rows, what is the largest number of trees that she can have in a​ row? The largest number of trees that she can have in a row is nothing.
Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer: 30 trees

Step-by-step explanation:

Elizabeth has 330 citrus trees and 180 palm trees

The largest number of trees that she can have in a row will base on the highest common factor between the two number of trees

330 = 2 × 3 × 5 × 11

180 = 2 × 2 × 3 × 3 × 5

HCF = 2 × 3 × 5

HCF = 30

The largest number of trees that she can have in a row is 30 trees.

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Answer:

  • adult: $7
  • student: $10

Step-by-step explanation:

Let a and s represent the prices of adult and student tickets, respectively.

  13a +12s = 211 . . . . . . ticket sales the first day

  5a +3s = 65 . . . . . . . ticket sales the second day

Subtracting the first equation from 4 times the second gives ...

  4(5a +3s) -(13a +12s) = 4(65) -(211)

  7a = 49 . . . . . . . simplify

  a = 7 . . . . . . . divide by 7

  5(7) +3s = 65 . . . . substitute into the second equation

  3s = 30 . . . . . . . subtract 35

  s = 10 . . . . . . . divide by 3

The price of one adult ticket is $7; the price of one student ticket is $10.

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Answer:

Step-by-step explanation:

Given

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