The blue line...
(1,2),(3,1)
slope = (1 - 2) / (3 - 1) = -1/2
there is a y int at (0,2.5) or (0,5/2)
it is shaded below the line....and it is a solid line
this inequality is :
y = -1/2x + 5/2
1/2x + y = 5/2
x + 2y = 5
x + 2y < = 5.....this is ur inequality
red line...
(0,4), (1,1)
slope = (1 - 4) / (1 - 0) = -3/1 = -3
there is a y int at (0,4)
it is shaded below the line...and it is a solid line
this inequality is :
y = -3x + 4
3x + y = 4
3x + y < = 4 ...this is ur inequality
summary :
ur 2 inequalities are :
x + 2y < = 5 and 3x + y < = 4
1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.
2. So f(x)=
3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions:
4. Now, f(0)=-5 so
5. the function is
where a can be any real number except 0
Answer:
(3,3)
Step-by-step explanation:
x + y - 6= 0
x- y = 0
Add the two equations together
x + y - 6= 0
x- y = 0
-------------------
2x - 6 = 0
Add 6 to each side
2x-6+6 = 0
2x = 6
Divide by 2
2x/2 = 6/2
x = 3
Now find y
x-y = 0
3 - y = 0
y = 3
Answer:
-x^2+5x+3
Step-by-step explanation:
Remove unnecessary parenthesis.
3x-2-x^2+2x+5
Collect like terms.
5x+3-x^2
Use the commutative property to reorder the terms.
-x^2+5x+3
You are right all the way