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Monica [59]
4 years ago
6

according to the National Automobile Dealers Association, a single dealership may employ people with as many as 57 different A.

job titles. B. technicians. C. salaries. D. specialists
Computers and Technology
1 answer:
soldi70 [24.7K]4 years ago
8 0

The only reasonable choice here is letter A - job titles. A single company needs the specialties coming from different expertise. In an automobile company, it could vary from sales to the engineering department. That's why a single dealership may employ people with as many as 57 different job titles.

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A file is to be shared among different processes, each of which has a unique number. The file can beaccessed simultaneously by s
Finger [1]

Answer:

int sumid=0;    /* Shared var that contains the sum of the process ids currently accessing the file */

int waiting=0;   /* Number of process waiting on the semaphore OkToAccess */

semaphore mutex=1;   /* Our good old Semaphore variable ;) */

semaphore OKToAccess=0;    /* The synchronization semaphore */

get_access(int id)

{

    sem_wait(mutex);

    while(sumid+id > n) {

        waiting++;

        sem_signal(mutex);

        sem_wait(OKToAccess);

        sem_wait(mutex);

    }

    sumid += id;

    sem_signal(mutex);

}

release_access(int id)

{

    int i;

    sem_wait(mutex);

    sumid -= id;

    for (i=0; i < waiting;++i) {

        sem_signal(OKToAccess);

    }

    waiting = 0;

    sem_signal(mutex);

}

main()

{

    get_access(id);

    do_stuff();

    release_access(id);

}

Some points to note about the solution:

release_access wakes up all waiting processes. It is NOT ok to wake up the first waiting process in this problem --- that process may have too large a value of id. Also, more than one process may be eligible to go in (if those processes have small ids) when one process releases access.

woken up processes try to see if they can get in. If not, they go back to sleep.

waiting is set to 0 in release_access after the for loop. That avoids unnecessary signals from subsequent release_accesses. Those signals would not make the solution wrong, just less efficient as processes will be woken up unnecessarily.

5 0
3 years ago
Please help in computer subject​
VMariaS [17]

Answer:

6. Read this quote from Ben Hogan below the photograph.

purple

"People have always been telling me what I can't do. I guess I have wanted to show them.

That's been one of my driving forces all my life."

31

What does this quote mean? Use at least two direct quotes from the text that give

examples of this quote.

A

urn

Julie Bahn

3 0
3 years ago
Read 2 more answers
OSHA standards appear in the ___________ and are then broken down into ____________.
miskamm [114]
OSHA standards appear in the <span>Code of Federal Regulations (CFR) and are then broken down into Parts</span>
3 0
3 years ago
Write a program that sorts an array of 10 integers using bubble sort. In the bubble sort algorithm, smaller values gradually “bu
blsea [12.9K]

Answer:

#include<iostream>

using namespace std;

int main(){

   //initialization

  int arr1[10] = {2,4,6,1,7,9,0,3,5,8};

  int temp;

   int size_arr;

   //nested for loop

  for(int i=0;i<size_arr-1;i++){

   for(int j=0;j<size_arr-i-1;j++){

       if(arr1[j]>arr1[j+1]){ //compare

               //swapping

           temp = arr1[j];

           arr1[j]=arr1[j+1];

           arr1[j+1]=temp;

       }

   }

  }

  //display the each element

  for(int i=0;i<10;i++){

   cout<<arr1[i]<<" ";

  }

    return 0;

}

Explanation:

Create the main function and declare the variable and defining the array with 10 values.

take the nested for loop, nested loop means loop inside another loop.

the outer loop traverse in the array from 0 to size-1.

and inside loop traverse from 0 to size -i-1, because for every cycle of the outer loop the one element is sorted at the end. so, we do not consider the element from the last for every cycle of the outer loop. That's why (size-i-1)

In the bubble sort, the first element compares with the second element and if the first id greater than the second then swap the value. so, for the above algorithm, we take the if statement and it checks the condition if the condition becomes true then the swap algorithm executes.

we take a third variable for swapping. after that, if the outer loop condition false it means all elements will traverse and then the loop will terminate.

and finally, take another for loop and display the output.

8 0
4 years ago
When you are checking an electric heating appliance, the first test made should be for
PSYCHO15rus [73]
The answer would be to first check the normal voltage supply so that there is enough electric current flowing for the electric heating appliance to work or run.
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4 years ago
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