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3 years ago

If an electric circuit has 30ohms and 10amps. How many volts the battery voltmeter should read?

Computers and Technology

1 answer:

Andreyy893 years ago

8 0

Given that,

Resistance, R = 30 ohms

Current, I = 10 A

To find,

The voltage of the battery.

Solution,

Let V is the voltage of the battery. We can use Ohm's law to find V.

Since, V = IR

Put all the values in the above formula.

V = 10×30

V = 300 Volt

So, the voltage of the battery in the voltmeter is 300 Volt.

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How do i unblock a website on a school computer if a school blocks it?

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Explanation:

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2 years ago

Define a lambda function that accepts one argument (a list of strings) and returns a list of only the words that start with an '

Grace [21]

Answer:

def Lambda(strList):
return list(filter(lambda s: (s.startswith("e")), strList))
print(Lambda(["meaning", "cart", "engine", "egg"]))

Explanation:

The solution code is written in Python 3.

Lambda function is an anonymous function. It is a function without any name and it is started with keyword lambda. To write a lambda function to filter the string started with an 'e', we can write a lambda expression, s.startswith("e") that work on one input strList. If any word from strList started with letter "e", the word will be added into a list generated by filter function. At the end, the Lambda function will return the list of strings as output.

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3 years ago

I was able to solve the question :))

Leviafan [203]

Answer:

ill take the points anyway

Explanation:

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3 years ago

let m be a positive integer with n bit binary representation an-1 an-2 ... a1a0 with an-1=1 what are the smallest and largest va

Ahat [919]

Answer:

Explanation:

From the given information:

$a_{n-1} , a_{n-2}...a_o$ in binary is:

$a_{n-1}\times 2^{n-1} + a_{n-2}}\times 2^{n-2}+ ...+a_o$

So, the largest number posses all $a_{n-1} , a_{n-2}...a_o$ nonzero, however, the smallest number has $a_{n-2} , a_{n-3}...a_o$ all zero.

∴

The largest = 11111. . .1 in n times and the smallest = 1000. . .0 in n -1 times

i.e.

$(11111111...1)_2 = ( 1 \times 2^{n-1} + 1\times 2^{n-2} + ... + 1 )_{10}$

$= \dfrac{1(2^n-1)}{2-1}$

$\mathbf{=2^n -1}$

$(1000...0)_2 = (1 \times 2^{n-1} + 0 \times 2^{n-2} + 0 \times 2^{n-3} + ... + 0)_{10}$

$\mathbf {= 2 ^{n-1}}$

Hence, the smallest value is $\mathbf{2^{n-1}}$ and the largest value is $\mathbf{2^{n}-1}$

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2 years ago

. When a system isdelivered over time, with each delivery (release) adding tothe

dexar [7]

Answer:

A. Incremental Development

Explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

The answer to this question is Incremental Development, this is when the development of the system is implemented little by little as time goes on. On the other hand phase development is when a development cycle is rolled out in phases such as the brainstorming phase, Construction phase, marketing , and roll out phase. Since this development doesn't contribute to the system's functionality it is not the correct answer.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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3 years ago