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3 years ago

If an electric circuit has 30ohms and 10amps. How many volts the battery voltmeter should read?

Computers and Technology

1 answer:

Andreyy893 years ago

8 0

Given that,

Resistance, R = 30 ohms

Current, I = 10 A

To find,

The voltage of the battery.

Solution,

Let V is the voltage of the battery. We can use Ohm's law to find V.

Since, V = IR

Put all the values in the above formula.

V = 10×30

V = 300 Volt

So, the voltage of the battery in the voltmeter is 300 Volt.

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What type of storage drive contains multiple spinning platters?

Gala2k [10]

The type of storage drive that contains multiple spinning platters is called; Hard disk drives

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Now, the correct answer to the question is hard disk drives. This is because a hard disk drive is comprised of a stack of spinning metal disks known as platters. Each spinning disk has trillions of tiny fragments that could possibly be magnetized in order to represent bits (1s and 0s in binary code).

Read more about Hard disk drives at; brainly.com/question/24498473

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2 years ago

Who wants to be my tutor?

anzhelika [568]

Answer:

i would but im not big brain

Explanation:

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3 years ago

Read 2 more answers

Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con

icang [17]

Answer:

The programming language is not stated;

I'll answer using C++

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

cout<<"Invalid Inputs";

}

else {

if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

cout<<"Right Angled";

}

else {

cout<<"Not Right Angled";

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

if(side1<=0 || side2 <= 0 || side3 <= 0) {

cout<<"Invalid Inputs";

}

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

cout<<"Right Angled";

}

If none of the above conditions is true, then the triangle is not a right angles triangle

else {

cout<<"Not Right Angled";

}

}

return 0;

Download cpp

4 0

3 years ago

Implement a Java program that creates math flashcards for elementary grade students. User will enter his/her name, the type (+,

jeka57 [31]

import java.util.Scanner;

public class JavaApplication44 {

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

System.out.print("Enter you name: ");

String name = scan.nextLine();

System.out.print("Enter your operation (+,-,*,/): ");

String operator = scan.nextLine();

System.out.print("Enter the range of the problems: ");

int ran = scan.nextInt();

System.out.print("Enter number of problems: ");

int problems = scan.nextInt();

int score = 0;

for (int i = 1; i <= ran; i++){

int first = (int)(Math.random()*ran);

int sec = (int)(Math.random()*ran);

System.out.print("Problem #"+i+": "+first + " "+operator+" "+sec+" = ");

int ans = scan.nextInt();

if (operator.equals("+")){

if (ans == first + sec){

System.out.println("Correct!");

score++;

}

else{

System.out.println("Wrong. The correct answer is "+(first+sec));

}

else if(operator.equals("-")){

if (ans == first - sec){

System.out.println("Correct");

score++;

}

else{

System.out.println("Wrong. The correct answer is "+(first - sec));

}

else if (operator.equals("*")){

if (ans == first * sec){

System.out.println("Correct");

score++;

}

else{

System.out.println("Wrong. The correct answer is "+(first * sec));

}

else if (operator.equals("/")){

if (ans == first / sec){

System.out.println("Correct");

score++;

}

else{

System.out.println("Wrong. The correct answer is "+(first / sec));

}

System.out.println(name+", you answered "+score+" questions correctly.");

}

I hope this helps!

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3 years ago

E whether True or False.

Natasha_Volkova [10]

Answer:

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