1 ) V = 1/3 * 18² * 3.14 * 6 = 2,034.72 mm³
2 ) V = 1/3 * 6² * 3.14 * 9 = 339.12 in³
3 ) V = 1/3 * 150² * 3.14 * 240 = 5,652,000 in³
5,652,000 : 12,000 = 471 weeks
Let distance form the pole = x and height of the hill = y ft
now we can set up 2 equayions
tan 18 = (40-y)/x
tan 14 = y/x
from second equation y = sxtan14 so we have:-
tan 18 = ( 40 - x tan 14) / x
x tan 18 = 40 - x tan 14
x(tan 18 + tan 14) = 40
x = 40 / (tan18 + tan 14) = 69.66 feet Answer
This is very similar to the last question:-
0.51No = No e^_0.0001t
t = ln 0.51 / 0.0001
= 6733 years
