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Andreyy89
3 years ago
9

In order to isolate the variable term in the equation 6 - 2x = -3 using the subtraction property of equality, which number

Mathematics
1 answer:
kvv77 [185]3 years ago
6 0

Answer:

x=9/2

Step-by-step explanation:

6-2x=-3

2x=6-(-3)

2x=6+3

2x=9

x=9/2

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0-449 is the most reasonable bc of how much the shipping costs
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Janae has 280 dimes in her piggy bank she has 10 times as many pennies how many pennies does Janae have
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Answer:

She has 28 pennies

Step-by-step explanation:

Janae has 280 dimes in her piggy bank she has 10 times as many pennies .

If she has 280 dimes in piggy bank

And has 10 times as many pennies

Let dimes= x

Let pennies= y

X= 10y

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3 years ago
How dou you solve for 6x+4y=24?
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You could first solve for y, assuming x is 0, and y = 6. Then solve for x, and that means y = 4.
3 0
3 years ago
(Show your working) I uploaded the question
svlad2 [7]

x^2 = the first integer

(x - 1)^2 = the second integer.

x^2 - (x - 1)^2 = ?

First, let's plug a number into our equation for x.

(2)^2 - (2 - 1)^2 = ?

4 - (1)^2 = ?

4 - 1 = 3

As we can see the difference is odd but it's also the sum of the two consecutive integers.

2 + 1 = 3.

This works for all numbers. Let's plug another number into our equation for x.

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Try any number and it will always be odd.

4 0
3 years ago
Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral
MAVERICK [17]

Answer:

a. \frac {2} {s-1} converges to s> 1.

b. \frac{3}{e^3 \left(s-5 \right)} converges to s> 5.

c. - \frac {2}{s + 3} converges to s> - 3.

d. \frac {s}{s^2 + 25} converges to s> 0.

e. \frac {10} {s^2 + 1} converges even s> 0.

f. \frac {12}{s^2 + 4} converges to s> 0.

g. -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4} converges to s> 0.

h. \frac {1} {s ^ 2 + 4} converges to s> 0.

Step-by-step explanation:

a. L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1} converges to s> 1.

b. L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)} converges to s> 5.

c. L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3} converges to s> - 3.

d. L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25} converges to s> 0.

e. L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1} converges even s> 0.

f. L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4} converges to s> 0.

g. L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4} converges to s> 0.

h. L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4} converges to s> 0.

7 0
3 years ago
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