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mafiozo [28]
3 years ago
8

13. A bag contains 8 red marbles, 4 purple marbles, 5 green marbles, 2 orange, and 1 blue

Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0

Answer:

a) 9 / 200

b) 13 / 100

Step-by-step explanation:

a) The two events are independent because they do not depend each other since the marbles are replaced. To find the total probability of two independent events, you multiply the probability of each event together.

Probability is represented by the amount of desirable outcomes over the total number of outcomes. The total would be the number of marbles, which is: 8 + 4 + 5 + 2 + 1 = 20 outcomes. The number of orange marbles is 2, so the outcomes where you do not pick orange are 20 - 2 or 18 outcomes. The probability of not picking an orange marble would be 18 / 20 or 9 / 10 (using the formula for probability).

There is one outcome where we can pick a blue marble, so the probability of picking a blue marble is 1 / 20. Now, we need to multiply the probabilities for each event: 1 / 20 * 9 / 10  = 9 / 200

b)There are 5 green marbles and 8 red marbles, so the the total outcomes where you pick green or red is 13. We put that over our total to get 13 / 20.

There are 4 purple marbles, so the probability of picking purple is 4 / 20 or 1 / 5. Now we multiply the two probabilities to get the total probability: 1 / 5 * 13 / 20 = 13 / 100

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Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1} and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0

Now, factoring the term:

x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}  the denominator becomes zero i.e

\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2  in the equation,

\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}

\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

  • brainly.com/question/1626495
  • brainly.com/question/2959656
  • brainly.com/question/2456302

#learnwithBrainly

5 0
3 years ago
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stepladder [879]

Answer:

the answer is C

Step-by-step explanation:

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2 years ago
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Anettt [7]

Answer:

-2<x<8

see below for graph

Step-by-step explanation:

First, we need to solve the inequality.

Inequality: |x-3|<5

Split into two equations:

x-3<5

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let's start with x-3<5

add 3 to both sides

x<8

now

x-3>-5

add 3 to both sides

x>-2

The graph is below

the intersection is the solution.

Notice how I made the maroon line go to the right- which shows that it's greater than (for x>-2) and the silver line go to the left, which shows that it's less than (for x<8)

the equation is -2<x<8

Hope this helps!

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Step-by-step explanation:

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9

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