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daser333 [38]
3 years ago
12

Trigonometry problem. Please show your solution and explain it. thank you !!

Mathematics
1 answer:
WINSTONCH [101]3 years ago
7 0
Cute one!
<span>
</span>Summarizing:
<span>sec(acot(tan(asin(sin(pi/3))))  .... use asin(sin(x))=x
</span>=sec(acot(tan(pi/3)))
=sec(acot(sqrt(3)))  ......... use acot(x)=atan(1/x)
=sec(atan(1/sqrt(3)))
=sec(atan(sqrt(3)/3))  .... evaluate atan(sqrt(3)/3), use unit circle
=sec(pi/6)
=1/cos(pi/6)...... evaluate cos(pi/6), use unit circle
=1/(sqrt(3)/2)  
=2/sqrt(3)  .... now rationalize
=2sqrt(3)/3

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aleksandr82 [10.1K]

Answer:

f(-7) = \bold{125}

Step-by-step explanation:

Given:

f(x) = 2x^2 - 3x + 6

f(-7) = 2(-7)^2 -3(-7) +6 \\ f(-7) = 2(49) -3(-7) +6 \\ f(-7) = 98 +21 +6 \\ f(-7) = 125

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3 years ago
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PLEASE HELP ME WITH THIS ALGEBRA QUESTION!! THANK YOU!!
lesantik [10]

Answer:

The first four terms of the sequence are: {-10,-23,-62,-179}

Step-by-step explanation:

Given recursive formula is:

a_n = 3a_{n-1}+7

First term = a1 = -10

The first term is already known. In order to find the next terms, we will put n=2,3,4 in the recursive formula.

Putting n=2

a_2 = 3a_{2-1}+7\\a_2 = 3a_1+7\\a_2 = 3(-10)+7\\a_2 = -30+7\\a_2 = -23

Putting n=3

a_3 = 3a_{3-1}+7\\a_3 = 3a_2+7\\a_3 = 3(-23)+7\\a_3 = -69+7\\a_3 = -62

Putting n=4

a_4 = 3a_{4-1}+7\\a_4 = 3a_3+7\\a_4 = 3(-62)+7\\a_4 = -186+7\\a_4 = -179

Hence,

The first four terms of the sequence are: {-10,-23,-62,-179}

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Nana76 [90]

Answer:

The answer to your question is 26

Step-by-step explanation:

Median is the middle number of a list order from lowest to highest.

Process

1.- Order the numbers from lowest to highest

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2.- Look for the middle number, if the total number of items is pair, take the 2 middle number and divide by two.

Middle numbers = 24 and 28

Median = (24 ´+ 28) / 2

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Median = 26

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It’s depends on how much of your grade the assignment was worth

Step-by-step explanation:

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