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daser333 [38]
3 years ago
12

Trigonometry problem. Please show your solution and explain it. thank you !!

Mathematics
1 answer:
WINSTONCH [101]3 years ago
7 0
Cute one!
<span>
</span>Summarizing:
<span>sec(acot(tan(asin(sin(pi/3))))  .... use asin(sin(x))=x
</span>=sec(acot(tan(pi/3)))
=sec(acot(sqrt(3)))  ......... use acot(x)=atan(1/x)
=sec(atan(1/sqrt(3)))
=sec(atan(sqrt(3)/3))  .... evaluate atan(sqrt(3)/3), use unit circle
=sec(pi/6)
=1/cos(pi/6)...... evaluate cos(pi/6), use unit circle
=1/(sqrt(3)/2)  
=2/sqrt(3)  .... now rationalize
=2sqrt(3)/3

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Answer: \frac{27}{125}

Step-by-step explanation:

Here the total numbers are 1,  4,  3,  7,  6

Since the total number of possible arrangement = 5\times 5 \times5 \times 5 \times 5=5^5

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Thus the possible arrangement that the first three digits will be odd numbers = 3\times 3\times 3\times 5\times 5=3^3\times 5^2

Thus, the probability that the first three digits of Irvings ID number will be odd numbers = the possible arrangement that the first three digits will be odd numbers / total possible arrangement =  \frac{3^3\times 5^2}{5^5} = \frac{3^2}{5^{5-2}}

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