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3 years ago

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Trigonometry problem. Please show your solution and explain it. thank you !!

1 answer:

WINSTONCH [101]3 years ago

7 0

Cute one!
<span>
</span>Summarizing:
<span>sec(acot(tan(asin(sin(pi/3)))) .... use asin(sin(x))=x
</span>=sec(acot(tan(pi/3)))
=sec(acot(sqrt(3))) ......... use acot(x)=atan(1/x)
=sec(atan(1/sqrt(3)))
=sec(atan(sqrt(3)/3)) .... evaluate atan(sqrt(3)/3), use unit circle
=sec(pi/6)
=1/cos(pi/6)...... evaluate cos(pi/6), use unit circle
=1/(sqrt(3)/2)
=2/sqrt(3) .... now rationalize
=2sqrt(3)/3

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Find two consecutive even integers such that the square of the second, decreased by twice the first is 52

Fiesta28 [93]

Let the first integer be $x$ . So, the next even number is $x+2$

Let's translate the formula: the square of the second is $(x+2)^2$ , twice the first is $2x$ . So, the equation is

$(x+2)^2 - 2x = 52$

Expand the square to get

$x^2+4x+4-2x = 52 \iff x^2+2x+4 = 52 \iff x^2+2x - 48 = 0$

The solutions to this equations are

$x = -8,\quad x = 6$

So, the possible consecutive even numbers are

$-8\text{ and } -6\quad\text{or}\quad 6\text{ and } 8$

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LenKa [72]

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D.

Step-by-step explanation:

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3 years ago

4x/5 + 2/3 + 1x/5 = x

Ksju [112]

Answer:

There are no solutions.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4x/5+2/3+1x/5=x

4/5x+2/3+1/5x=x

(4/5x+1/5x)+(2/3)=x(Combine Like Terms)

x+23=x

x+23=x

Step 2: Subtract x from both sides.

x+2/3−x=x−x

2/3=0

Step 3: Subtract 2/3 from both sides.

2/3−2/3=0−2/3

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Answer:

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6 0

3 years ago

Read 2 more answers

What is the answer? please tell me i am desperate!?

solniwko [45]

Okay so this is easy conversion.
40 quarters=10$
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