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9966 [12]
3 years ago
11

To win the long jump, you need to jump a distance greater than 2.25 m. Your personal best jump is 2.1 m. How much do you need to

increase your personal best by to win?
Mathematics
2 answers:
DiKsa [7]3 years ago
5 0
Find the difference of both numbers: 0.15
Since it has to be greater, any number larger than 0.15 will work.
atroni [7]3 years ago
3 0
U would need 0.25  yeah this is corect
You might be interested in
A patio has an area of 1420 square feet. If the length is 45 1/2, what is the width​
Anni [7]

[ Answer ]

\boxed{Width \ = \ 31\frac{19}{91} \ Ft^{2}}

[ Explanation ]

Area = 1420

Width = 45\frac{1}{2}

Area For Rectangle: Length · Width

Use division to find width:

1420 ÷ 45\frac{1}{2}

Convert mixed numbers to fractions:

1420 = \frac{1420}{1}

45\frac{1}{2} = \frac{91}{2}

\frac{1420}{1} ÷ \frac{91}{2}

Use mixed multiplication:

\frac{1420*2}{1*91}

= \frac{2140}{91}

Simplify:

= 31\frac{19}{91}

\boxed{[ \ Eclipsed \ ]}

7 0
3 years ago
Answers should be exact decimals (please do not leave as fractions or unfinished calculations).
aksik [14]

Answer:

P(rolling the die results in a 3 or a 6)=0.3333

P(rolling the die results in not getting a 6)=0.8333

P(rolling the die results in the number being either greater than 2 or less than 5)=0.3333

P(rolling the die results in an even number or a 5)=0.6667

P( rolling the die twice results in a 6 followed by a 4)=0.0278

P(rolling the die three times results in all 6's)=0.0046

Step-by-step explanation:

a)

As the all outcomes are equally likely, so each number has equal probability of occurring.

For six sided die the sample space is {1,2,3,4,5,6} and each outcome has equal probability of 1/6.

1)

P(rolling the die results in a 3 or a 6)

P(rolling the die results in a 3 or a 6)=P(3)+P(6)=1/6+1/6=2/6=1/3

P(rolling the die results in a 3 or a 6)=0.3333

P(rolling the die results in not getting a 6)

P(rolling the die results in not getting a 6)=1-P(6)=1-1/6=5/6

P(rolling the die results in not getting a 6)=0.8333

P(rolling the die results in the number being either greater than 2 or less than 5)

number either greater than 2 or less than 5={3,4}

P(rolling the die results in the number being either greater than 2 or less than 5)=2/6=1/3

P(rolling the die results in the number being either greater than 2 or less than 5)=0.3333

P(rolling the die results in an even number or a 5)

number is an even number or a 5={2,4,5,6}

P(rolling the die results in an even number or a 5)=4/6=2/3

P(rolling the die results in an even number or a 5)=0.6667

P( rolling the die twice results in a 6 followed by a 4)

For six sided die rolled twice the sample space is

S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}.

n(S)=6²=36.

rolling the die twice results in a 6 followed by a 4={(6,4)}

P( rolling the die twice results in a 6 followed by a 4)=1/36.

P( rolling the die twice results in a 6 followed by a 4)=0.0278

P(rolling the die three times results in all 6's)

When three die are rolled the number of outcomes=n(S)=6³=216.

rolling the die three times results in all 6's={(6,6,6)}

P(rolling the die three times results in all 6's)=1/216

P(rolling the die three times results in all 6's)=0.0046

Note: All answers are rounded to four decimal places.

8 0
3 years ago
Plz help giveing 10 pints
erik [133]

Just plug in the variables so you would have -(-3) - 4^2 / 4(-3) - (5-4). Next you solve it for 3 - 16 / -12 - 1, -13/-13 = 1. Your final answer is 1. If this is right could you possibly give me brainliest? Hope this helped.

7 0
3 years ago
I need help please and thank you
Rom4ik [11]

Answer:

144°

Step-by-step explanation:

Hope this helps :)

8 0
3 years ago
9x²+bx+100 as a perfect square​
jok3333 [9.3K]

Step-by-step explanation:

9x²+bx+ 100

(3x)²+ bx + 10²

(3x)² + 10² + bx

(3x)² + 10² + bx

3 0
3 years ago
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